All categories

3 years ago

Can someone help me with this question? I’ll mark as brainliest if correct!

Mathematics

2 answers:

Reika [66]3 years ago

7 0

Answer:

which diagram model the story

the answer is 1 b { 9 9 9 9 9 9 9 9 9

the first one

which equation models the story

the answer is b/10=9

please mark as brainliest

Travka [436]3 years ago

5 0

For both answers it is the second option

You might be interested in

Sara weight 25 pound-more than amber if together they weight 205 what is the weight of sara ??

serg [7]

Let Sara weight =x+25
amber wiegh =x
x+25+x=205
x= 90
Sara weight is 90+25= 115

7 0

2 years ago

The area of a trapezoid is given by the formula A=h/2(a+b) .<br><br> Solve the formula for b.

Komok [63]

Answer:

(2A)/h -a =b

Step-by-step explanation:

A= [h(a+b)]/2 I rewrote the formula, because h and a+b are in the numerator.

2A=h(a+b) Multiply both sides of equation by 2

(2A)/h= a+b Divide both side by h

(2A)/h -a= b Subtract a from both sides

4 0

3 years ago

A store is holding a grand opening promotion. Every 3rd customer receives a free key chain and every 4th customer receives a fre

Archy [21]

Answer:

12th Customer

Step-by-step explanation:

We have to find the lcm (lowest common multiple) of the number.

We do that by taking their multiples. Watch down below

3 x 1 = 3 4 x 1 = 4

3 x 2 = 6 4 x 2 = 8

3 x 3 = 9 4 x 3 = 12

3 x 4 = 12

See how they both have a 12 as their first lcm.

So the 12th customer gets both items.

Glad to help!

8 0

3 years ago

1. Consider the population model dP dt = 0.2P 1 − P 135 , where P(t) is the population at time t. (a) For what values of P is th

Kryger [21]

Answer:

$P = 0$ OR $P = 135$

$P > 0$ and $P < 135$

Generally the carrying capacity is can be defined as the highest amount of population and environment can support for an unlimited duration or time period

$P = 67.5$

Step-by-step explanation:

From the question we are told that

The population model is $\frac{dP}{dt} = 0.2P(1 - \frac{P}{135} )$

Generally at equilibrium

$\frac{dP}{dt} = 0$

$0.2P = 0$

=> $P = 0$

$(1 - \frac{P}{135} ) = 0$

=> $P = 135$

Thus at equilibrium P = 0 or P = 135

Generally when the population is increasing we have that

$\frac{dP}{dt} > 0$

$0.2P > 0$

=> $P > 0$

and

$(1 - \frac{P}{135} ) > 0$

$P < 135$

Now when the first value of P i.e $P< 0$ for $\frac{dP}{dt} > 0$

$P_2 > 135$

So when population increasing the values of P are

$P > 0$ and $P < 135$

So to obtain initial values of P where the population converge to the carrying capacity as $t \to [\infty]$

The rate equation can be represented as

$\frac{dP}{dt} = \frac{1}{5}P (1 - \frac{P}{135} )$

So we will differentiate the equation again we have that

$\frac{d^2 P}{dt^2} = \frac{(1 - \frac{P}{135} )}{5} - \frac{P}{675}$

Now as $t \to [\infty]$

$\frac{d^2 P}{dt^2} \to 0$

$\frac{(1 - \frac{P}{135} )}{5} - \frac{P}{675} = 0$

=> $\frac{(1 - \frac{P}{135} )}{5} = \frac{P}{675}$

=> $P = 67.5$

5 0

3 years ago

What is in the final step in the problem-solving process?

Alla [95]

<span>The final step in the problem-solving process is check you work.Because first reading the problem will understand the situation and we can decide how the operations can be used to solve the problem and performing the work neatly and finally checking and rechecking the solution is an best option.</span>

6 0

3 years ago

Read 2 more answers