Help with f(x) = 2.2^x for f (-2)
2 answers:
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<em>Your Answer: </em>A.) (2 , 5) <u>I also provided the steps.</u>
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Answer:
±√58 ≈ ±7.616
Step-by-step explanation:
The linear combination of sine and cosine functions will have an amplitude that is the root of the sum of the squares of the individual amplitudes.
|x| = √(3² +7²) = √58
The motion is bounded between positions ±√58.
_____
Here's a way to get to the relation used above.
The sine of the sum of angles is given by ...
sin(θ+c) = sin(θ)cos(c) +cos(θ)sin(c)
If this is multiplied by some amplitude A, then we have ...
A·sin(θ+c) = A·sin(θ)cos(c) +A·cos(θ)sin(c)
Comparing this to the given expression, we find ...
A·cos(c) = 3 and A·sin(c) = -7
We know that sin²+cos² = 1, so the sum of the squares of these values is ...
(A·cos(c))² +(A·sin(c))² = A²(cos(c)² +sin(c)²) = A²(1) = A²
That is, A² = (3)² +(-7)² = 9+49 = 58. This tells us the position function can be written as ...
x = A·sin(θ +c) . . . . for some angle c
x = (√58)sin(θ +c)
This has the bounds ±√58.
Answer:
She should have multiplied one half (4)(3.5) by 5 squared.
Step-by-step explanation:
We are given that
Base of triangle=b=4 cm
Height of triangle=h=3.5 cm
Area of triangle=
After enlarged
Scale factor=5
New base of enlarged triangle=b'=4(5) cm
Height of enlarged triangle=h'=3.5(5) cm
Area of enlarged triangle=
But Beth wrote
Area of enlarged triangle=
She should have multiplied one half (4)(3.5) by 5 squared.