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SOVA2 [1]
2 years ago
11

A line has a slope of 10 and includes the points (3, n) and (4,0). What is the value of n? n =

Mathematics
1 answer:
ExtremeBDS [4]2 years ago
8 0

Answer:

The value of n = -10  

Step-by-step explanation:

Given the points

  • (3, n)
  • (4,0)

Finding the slope between (3, n) and (4,0)

\left(x_1,\:y_1\right)=\left(3,\:n\right),\:\left(x_2,\:y_2\right)=\left(4,\:0\right)

As slope = 10

using the formula

Slope  =  [y₂ - y₁] /  [x₂ - x₁]

so substituting the values

      10   =  [0 - n] / [4 - 3]

      10   = -n / 1

     10 = -n

     n = -10    

Therefore, the value of n = -10  

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What is the slope of a l8ne that contains the points (34,12) and (32,48)
Vlad [161]
I hope this helps you





slope (34-32)= 12-48




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7 0
3 years ago
How do you do this problem?
faust18 [17]

The volume of the original cylinder is

... V = π·r²·h

For r=1 and h=1, this is

... V = π·1²·1 = π

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... V = 1.089π = π·1.1²·(1-k)

... 1.089/1.21 = 1-k

... k = 1 - 1.089/1.21 = 1 - 0.9 = 0.1 = 10%

The appropriate choice is (B) 10.

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In a group of a hundred and fifty students attending a youth workshop in mombasa, 125 of them are fluent in kiswahili, 135 in en
jek_recluse [69]

Answer:

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

Step-by-step explanation:

<u><em>Step(i):</em></u>-

Given total number of students n(T) = 150

Given 125 of them are fluent in Swahili

Let 'S' be the event of fluent in  Swahili language

n(S) = 125

The probability that the fluent in  Swahili language

P(S) = \frac{n(S)}{n(T)} = \frac{125}{150} = 0.8333

Let 'E' be the event of fluent in English language

n(E) = 135

The probability that the fluent in  English language

P(E) = \frac{n(E)}{n(T)} = \frac{135}{150} = 0.9

n(E∩S) = 95

The probability that the fluent in  English and Swahili

P(SnE) = \frac{n(SnE)}{n(T)} = \frac{95}{150} = 0.633

<u><em>Step(ii):</em></u>-

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = P(S) + P(E) - P(S∩E)

           = 0.833+0.9-0.633

           = 1.1

<u><em>Final answer:-</em></u>

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

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