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2 years ago

Help last question!!! Please

Mathematics

1 answer:

torisob [31]2 years ago

7 0

Answer:

p=9

Step-by-step explanation:

ching baked -6p based off what it says

15-(-6)=9

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Help me with this pls

Rufina [12.5K]

Answer:

b^-6

Step-by-step explanation:

(b^-2) / (b^4) = b^(-2 - 4)

3 0

3 years ago

Read 2 more answers

Help me please with 3-111

LenKa [72]

Last Question

Because this may not be the question you want, I'll omit the first step which should be done with latex. The key to all of these except C is to invert the second fraction (turn the second fraction upside down) and multiply.

$\dfrac{6}{5} * \dfrac{-2}{3}$

=(6*-2) / (5*3) = - 12/15 = -4/5

$\dfrac{7}{4} *\dfrac{5}{3}$

= (7*5) / (4*3) = 35 / 12 = 2 11/12

Impossible to do 4/0 cannot be done.

$\dfrac{-2}{3} /\dfrac{-5}{4}=\dfrac{-2}{3} *\dfrac{-4}{5}$

= (-2*-4)/(3*5) =

8/15

4 0

3 years ago

1. A clerk is paid P 45.25 per hour for 40 hours a week, 1.50 times the

Ierofanga [76]

Answer:

The clerk's total earnings is P520.375

Step-by-step explanation:

Given

Earnings = $45.25 per hour

Overtime = 1.5 * regular earnings

Holiday = double regular earnings

Required

Determine his earnings for 5 hours (overtime) and 2 hours (holiday)

From the question, we understand that

Regular Earnings = P45.25

Overtime Earnings = 1.5 * P45.25

Overtime Earnings = P67.875

Overtime Earnings for 5 hours = 5 * P67.875

Overtime Earnings for 5 hours = P339.375

Holiday Earnings = 2 * Regular Earnings

Holiday Earnings = 2 * P45.25

Holiday Earnings = P90.5

Holiday Earnings for 2 hours = 2 * P90.5

Holiday Earnings for 2 hours = P181.0

The clerk's total earnings is calculated as thus:

Total = Overtime Earnings for 5 hours + Holiday Earnings for 2 hours

Total = P339.375 + P181.0

Total = P520.375

5 0

2 years ago

Read 2 more answers

What is the missing value in x2y8 · x3y? = x5y5?

sweet-ann [11.9K]

Answer:

-3

Step-by-step explanation:

To find:

The value of '?' in the following expression:

$x^2y^8.x^3y^? = x^5y^5$

Solution:

First of all, let us have a look at a few rules of the exponents:

$1.\ a^b.a^c=a^{b+c}$

$2.\ a^b.a^{-c}=a^{b-c}$

Let us apply these rules and try to find out the missing value ('?') in the given expression.

Left Hand Side (LHS):

$x^2y^8.x^3y^?\\\Rightarrow x^2.x^3.y^8.y^?\\\Rightarrow x^{2+3}y^{8+?}\\\Rightarrow x^{5}y^{8+?}$

Now, let us compare the LHS with RHS, we get:

$x^{5}y^{8+?} = x^{5}y^{5}$

Dividing with $x^5$ on both sides:

$y^{8+?} = y^5\\\Rightarrow 8+? = 5\\\Rightarrow ? = 5-8 \\\Rightarrow ? =-3$

Therefore, the missing value in the expression is <em>-3.</em>

4 0

3 years ago

Oliver picks a 4-digit even number that is greater than 3000.

Irina18 [472]

Answer:

Hello,

why not 700 ?

Step-by-step explanation:

$n=\overline{abcd}\\a\in \{3,4,5,6,7,8,9\}: 7\ possibilities\\b\in\{4,8\} :2\ possibilities\ :0 \ in\ USA\ is\ not\ a\ multiple\ of\ 4\\c \in\{0,1,2,3,4,5,6,7,8,9}: 10\ possibilities\\d \in \{0,2,4,6,8\}:5\ possibilities\\$

7*2*10*5=700

Impossible to reach 3000 since 2nd digit is 4 or 8.

8 0

2 years ago