(5rs-1t3)(-3r2st)
-30r^2s^2t+18rst^2
Answer:
30.28 yd²
Step-by-step explanation:
Area enclosed = area of trapezoid + area of semicircle
= ½(a + b)*h + ½(πr²)
Where,
a = 5 yd
b = 2 + 5 = 7 yd
h = 4 yd
r = ½(4) = 2 yd
Plug in the known values
Area enclosed = ½(5 + 7)*4 + ½(π*2²)
Area enclosed = ½(12)*4 + ½(π*4)
= 6*4 + π*2
= 24 + 2π
= 30.2831853
≈ 30.28 yd² (2 decimal places)
Answer:
(1.63,4.18)
Step-by-step explanation:
1) look at the graph below: they intersect at about (1.5,4)
lets solve the systems by substitution:
since both equations are equal to y lets substitute the second equation into the first:
-6x+14=5x-4
-6x-5x=-14-4
-11x=-18
x=1.63
lets substitute x in the first equation:
5(1.63)-4=4.18
Hope this helps!
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Step-by-step explanation: