The volume of the metal box if the box was completely solid (V1), is:
V1=(12 inches)³
V1=1728 inches³
As there are 3 inches of metal on both sides, the widht if the metal box was not completely solid, is:
W=12 inches-(3 inchesx2)
W=6 inches
Then, the volumen of the no solid metal box is:
V2=(6 inches)³
V2= 216 inches³
Therefore, the volume of metal needed to smelt the cubical metal box, is:
V3=V1-V2
V3=1728 inches³-216 inches³
V3=1512 inches³
The second one i believe
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Simplify
-3x + 9 = -3x - 3
Subtract 9 (both sides)
-3x = -3x - 12
Add 3x to both sides
0 = -12, this cannot be true
Answer: no solution
To convert m/s to mi/min we have to find conversion factor first
1 mile = 1609.344 m
1m = 1/1609.344 miles
1 min = 60 s
1s = 1/60 min
Let’s put mi/min instead of m/s according to equations above
m/s = [1/1609.344 miles] / [1/60 min]
The conversion factor is
f = 60 / 1609.344
Now we can convert m/s to mi/min
V (mi/min) = 2.998 ∙ 108 m/s ∙ f = 2.998 ∙ 108 ∙ (60 / 1609.344) = 1.118 ∙ 107 mi/min
Answer: V = 1.118 ∙ 107 mi/min
Hope u have a good day of learning
