Find the median of the following data set 6,2,59,12,11,9,9,54,54,46,2,32,43,11
Aleonysh [2.5K]
By arranging the numbers in ascending order we get,
2, 2, 6, 9, 9, 11, 11, 12, 32, 43, 46, 54, 54, 59
The 2 middle numbers are:
11, 12
To find the median we have to add them and divide them by 2
So, (11+12)÷2
23÷2
11.5
Answer : 1/2 x 3/5 = 3/10.
Answer:
v = 15/7, or 2.14
Step-by-step explanation:
Find a common denominator, or multiply both denominators by each other, and well as the numerator.
v/5 = 3/7 can be written as 7v/35 = 15/35
multiplying both sides with 35, we are left with 7v = 15
v = 15/7, or 2.14
Answer:
See steps below
Step-by-step explanation:
a)
The cdf associated with f is
for 0<x<1
<h3>See picture 1
</h3>
The median is a point x such that
F(x) = ½
so, the median is
![\bf 1-(1-x)^3=1/2\rightarrow (1-x)^3=1/2\rightarrow \boxed{x=1-\sqrt[3]{2}}](https://tex.z-dn.net/?f=%5Cbf%201-%281-x%29%5E3%3D1%2F2%5Crightarrow%20%281-x%29%5E3%3D1%2F2%5Crightarrow%20%5Cboxed%7Bx%3D1-%5Csqrt%5B3%5D%7B2%7D%7D)
The 25th percentile equals the 1st quartile and is a point x such
F(x) = ¼
and the 25th percentile is
![\bf 1-(1-x)^3=1/4\rightarrow (1-x)^3=3/4\rightarrow \boxed{x=1-\sqrt[3]{3/4}}](https://tex.z-dn.net/?f=%5Cbf%201-%281-x%29%5E3%3D1%2F4%5Crightarrow%20%281-x%29%5E3%3D3%2F4%5Crightarrow%20%5Cboxed%7Bx%3D1-%5Csqrt%5B3%5D%7B3%2F4%7D%7D)
b)
The cdf associated with f is
for x>1
<h3>See picture 2
</h3>
The median is
The 25th percentile is
c)
f(x) = 1/3 for 0<x<1 or 2<x<4
The cdf associated with f is
for 0<x<1
for 2<x<4
<h3>See picture 3
</h3>
The median is
The 25th percentile is
