Well 40 times 6 is 240 which means that you don't have to round.
The answer is (-21, 13) for The second endpoint.
Let's start by calling the known endpoint L and the unknown K. We'll call the midpoint M. In order to find this, we must first note that to find a midpoint we need to take the average of the endpoints. To do this we add them together and then divide by 2. So, using that, we can write a formula and solve for each part of the k coordinates. We'll start with just x values.
(Kx + Lx)/2 = Mx
(Kx + 1)/2 = -10
Kx + 1 = -20
Kx = -21
And now we do the same thing for y values
(Ky + Ly)/2 = My
(Ky + 7)/2 = 10
Ky + 7 = 20
Ky = 13
This gives us the final point of (-21, 13)
You can set up rations to do this.
So we know that they accept 2:5.
So It would be 180: 450.
A recursive pattern is a sequence of numbers that entails a pattern between succeeding numbers. in this case, we can see that sequence 2 has an arithmetic difference of 9, that is the proceeding terms are 40, 49, 58.. The third one has also an arithmetic difference that is increasing by 3 each. The answer then is A which has no pattern.
Answer:
The height of the ball after 3 secs of dropping is 16 feet.
Step-by-step explanation:
Given:
height from which the ball is dropped = 160 foot
Time = t seconds
Function h(t)=160-16t^2.
To Find:
High will the ball be after 3 seconds = ?
Solution:
Here the time ‘t’ is already given to us as 3 secs.
We also have the relationship between the height and time given to us in the question.
So, to find the height at which the ball will be 3 secs after dropping we have to insert 3 secs in palce of ‘t’ as follows:
h(3)=160-144
h(3)=16
Therefore, the height of the ball after 3 secs of dropping is 16 feet.
