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3 years ago

Please help me with this question. Please, this is due today. Helppppp meeee

Mathematics

2 answers:

Lynna [10]3 years ago

6 0

Answer:

Step-by-step explanation:

calm down ...

don't let a strange problem description overwhelm you right away.

always try to work with the things you know first. and only when you run into something you really don't know, start thinking.

so, perimeter.

your know, what a perimeter is ? it is the circumference. all the side lengths added together. the answer to "how much distance would you have to go, to walk all the way around it one time".

so, what is the circumference of the square based on what we know ?

well, it has 4 equal sides, right ? otherwise it would not be a square.

so, the perimeter is 4×(x+2) = 4x + 8

that is perfectly fine.

now to the next part we know.

the perimeter of the triangle is the sum of its 3 sides (otherwise it would not be a triangle).

an isoceles triangle is a special triangle that has 2 equal sides.

so, we actually know all 3 sides (at least relatively) :

x+3

x+5

and ... another

x+3 (because of the isoceles property)

so, the perimeter is

x + 3 + x + 3 + x + 5 = 3x + 11

alright.

and now we also know that both perimeters are of equal length.

what did that mean ?

that both expressions deliver the same result.

therefore,

4x + 8 = 3x + 11

aha !

x = 3

bingo !

therefore, the side lengths of the triangle are

x+3 = 3+3 = 6 (both sides in the top)

x+5 = 3+5 = 8

and that's all there is to it.

it is really not necessary to panic don't you think ?

zzz [600]3 years ago

5 0

Answer:

6by6by8

Step-by-step explanation:

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Prime number 157, 1057, 263, 3163

Sergio [31]

157, 263, and 3163 are all prime numbers

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3 years ago

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balu736 [363]

Answer:

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Step-by-step explanation:

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3 years ago

Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in s

wolverine [178]

Answer:

x^4 - 14x^2 - 40x - 75.

Step-by-step explanation:

As complex roots exist in conjugate pairs the other zero is -1 - 2i.

So in factor form we have the polynomial function:

(x - 5)(x + 3)(x - (-1 + 2i))(x - (-1 - 2i)

= (x - 5)(x + 3)( x + 1 - 2i)(x +1 + 2i)

The first 2 factors = x^2 - 2x - 15 and

( x + 1 - 2i)(x +1 + 2i) = x^2 + x + 2ix + x + 1 + 2i - 2ix - 2i - 4 i^2

= x^2 + 2x + 1 + 4

= x^2 + 2x + 5.

So in standard form we have:

(x^2 - 2x - 15 )(x^2 + 2x + 5)

= x^4 + 2x^3 + 5x^2 - 2x^3 - 4x^2 - 10x - 15x^2 - 30x - 75

= x^4 - 14x^2 - 40x - 75.

7 0

4 years ago

F(x)=2x^2-3x+7 evaluate f(-2)

Vilka [71]

Answer:

Step-by-step explanation:

Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?

Let p(x)=kpx+dp and q(x)=kqx+dq than

f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7

p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7

(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)

So you want:

−2kpk2q=0

and

kpkq=−1

and

2kpd2p−3kpdq+7=0

Now I amfraid this doesn’t work as −2kpk2q=0 that either kp or kq is zero but than their product can’t be anything but 0 not −1 .

Answer: there are no such linear functions.

6 0

3 years ago

Octagon ABCDEFGH and its dilation, octagon A'B'C'D'E'F'G'H', are shown on the coordinate plane below:

Vaselesa [24]

Answer:

2) 2

Step-by-step explanation:

Transformation is the movement of a point from its initial location to a new location. Types of transformation are reflection, translation, rotation and dilation.

Dilation is the enlargement or reduction of the size of an object. If a figure with point A(x, y) is dilated by a scale factor of k about the center of the origin, the new point would be at (kx, ky). If k < 1 it is a reduction and if k > 1 it is an enlargement.

The octagon ABCDEFGH has vertices at A(3, 1), B(3, -1), C(1, -3), D(1, -3), E(-3, -1), F(-3, 1), G(-1,3) and H(1, 3)

Octagon ABCDEFGH is then dilated about the origin to form octagon A'B'C'D'E'F'G'H' with vertices at A'(6, 2), B'(6, -2), C'(2, -6), D'(2, -6), E'(-6, -2), F'(-6, 2), G'(-2,6) and H'(2, 6)

A = (3, 1) and A' = (6, 2) = [2(3), 2(1)]

Therefore octagon ABCDEFGH was dilated by a scale factor of 2 to form octagon A'B'C'D'E'F'G'H'

6 0

3 years ago