Given
Height (length) of the anchor dropped from the boat = 75 feet
Distance of the treasure from the anchor = 40 feet
Solution
The dropped at the bottom makes an angle of 90 degree . Therefore making an right triangle with the chest and boat
By Pythagoras theorem
AC^2 = AB^2 + BC^2
(AC = distance of the treasure from the boat
AB = height of the anchor dropped from the boat
BC = the distance of treasure from the anchor)
AC^2 = 75^2 + 40^2
AC^2 = 5325 +1600
AC^2 = 6925
AC = 25 * (under root 11)
Therefore they have cover a distance of 25 * (under root 11)
It is 5 times the size of the object
Answer: 660 cm²
Step-by-step explanation:
Surface area of a cylinder = 2πr² ± 2πrh = 2πr ( r + h )
π = 22/7
r = 6 cm
h = 11.5 cm
Lateral surface area = 2 x 22/7 x 6 ( 6 + 11.5 )
= 660 cm²
The general slope-intercept form is given by

, where

is the slope and

is the y-intercept.
Let's find the slope first. Remember that the slope given by two points is

. So, using the two given points,



Now, we know that

. To find

, let's just plug in the x and y coordinates for one of the points and solve for b:



Thus, the equation of the line in slope-intercept form is
Like specifically 3.75 times 82