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Naddik [55]
3 years ago
10

Help PLEASE I FORGOT HOW TO DO THIS LMDAOAOAOAOAOOA

Mathematics
2 answers:
Nezavi [6.7K]3 years ago
6 0

Answer:

1056

Step-by-step explanation:

)22 times 6) times 8

kenny6666 [7]3 years ago
5 0

Answer:

1,164 Yards Squared

Step-by-step explanation:

(9 x 4) x 3 = 108

(22 x 8) x 6 = 1,056

1,056 + 108 = 1164

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How much greater is 3 1/4 than 2 1/2
Doss [256]

Answer:

3/4 greater

Step-by-step explanation:

3.25 - 2.5 = 0.75

0.75= 3/4

8 0
3 years ago
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“Write a linear equation that is perpendicular to 2x-5y=5 and passes through the point (2,-9).
k0ka [10]
Okay so you are correct with the gradient of the perpendicular line it is -5/2 however the equation is not y= -5/2 -1 because it is a new Line and has a new y-intercept therefore its Y=-5/2 + C but you have corrected that when doing the formula and have got the right answer
4 0
3 years ago
Can someone help me, thanks! :D
Strike441 [17]

Answer:

hose

Step-by-step explanation:

7 0
4 years ago
What does 2.6x10 to the7 th power
ss7ja [257]
This is called scientific notation. To simplify, just do 10 to the 7th (1 with 7 zero's behind it) to get 10,000,000 (10 million) then multiply that by 2.6 to get your final answer:
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6 0
3 years ago
Show that the velocity of the particle at time t is given by v(t)=70t(3t2+8)2 .
RideAnS [48]

Question:

A particle moves along the x-axis so that its position at time t>0 is given by x(t)=\frac{t^2 -9}{3t^2 +8}

Show that the velocity of the particle at time t is given by v(t) = \frac{70t}{(3t^2 + 8)^2}

Answer:

v(t) = \frac{70t}{(3t^2 + 8)^2}

Step-by-step explanation:

Given

x(t)=\frac{t^2 -9}{3t^2 +8}

Required

Show that:

v(t) = \frac{70t}{(3t^2 +8)^2}

To calculate v(t), we use:

v(t) = x'(t)

So, we have:

x(t)=\frac{t^2 -9}{3t^2 +8}

Apply quotient rule

x'(t) = \frac{vu' - uv'}{v^2}

Where

u =t^2 - 9

v=3t^2 + 8

So:

u =t^2 - 9

u' = 2t

v=3t^2 + 8

v' = 6t

So, we have:

x'(t) = \frac{vu' - uv'}{v^2}

x'(t) = \frac{(3t^2 + 8) * 2t - (t^2 - 9) * 6t}{(3t^2 + 8)^2}

Expand the numerator

x'(t) = \frac{6t^3 + 16t - 6t^3 + 54t}{(3t^2 + 8)^2}

Collect like terms

x'(t) = \frac{6t^3 - 6t^3+ 16t  + 54t}{(3t^2 + 8)^2}

x'(t) = \frac{70t}{(3t^2 + 8)^2}

Recall that:

v(t) = x'(t)

v(t) = \frac{70t}{(3t^2 + 8)^2}

<em>Proved</em>

5 0
3 years ago
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