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IrinaVladis [17]
3 years ago
12

I NEEDDDDD HELPPPPPPPPPP!!!!

Mathematics
1 answer:
lesya692 [45]3 years ago
7 0

Answer:

36 units squared

Step-by-step explanation:

10 times 10 - 4 times 4  = 100-16 = 84, take the square root of 84 = 9.12 which rounds to 9, now that we found the height, we use the area of a triangle formula, A=bh/2, so the base is 8 times height 9 = 72 divided by 2 = 36

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What is the LCD for the problem below.<br><br><br>5/8−1/7
shepuryov [24]

Answer:

The lowest common denominator or least common denominator (abbreviated LCD) is the least common multiple of the denominators of a set of fractions. It is the smallest positive integer that is a multiple of each denominator in the set. Fractions write with fraction bar / like 3/4 .

4 0
3 years ago
BRAINLIEST BRAINLIEST <br> Please answer number 2 thank you
bija089 [108]

Answer:

$28

Step-by-step explanation:

Time = 4 hours

Charge = $7 / hour

Multiply those two numbers:

4 hour × $7 / hour = $28

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Hopefully this answer helps you :)

4 0
3 years ago
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Tatiana [17]

Answer:

d

Step-by-step explanation:

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3 years ago
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Quadrilateral ABCD is similiar to quadrilateral EFGH. The lengths of the three longest sides in quadrilateral ABCD are 60 feet,
Ivan

Answer:

15 feet

Step-by-step explanation:

Quadrilateral ABCD has a scale facter of 2.5 over the quadrilateral EFGH. The order of ABCD is 60, 40, 30, and x, EFGH has y, z, 12, and 6.

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7 0
4 years ago
The sum of two numbers is 0. Twice the smaller number subtracted from 3 times the larger number is 10. Let x represent th larger
slava [35]
The sum of two numbers is zero.
x + y = 0
y = -x

<span>Twice the smaller number subtracted from 3 times the larger number is 10.
Let x represent the larger number and y represent the smaller number.

Twice the smaller number: 2y

3 times the larger number: 3x

</span>Twice the smaller number subtracted from 3 times the larger number is 10. 
3x - 2y = 10

-2y = -3x + 10

y = 3/2 x - 5

The equations are:

y = -x
y = 3/2 x - 5

The answer is the first choice.
5 0
3 years ago
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