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Degger [83]
2 years ago
13

What is the area of the half circle below?2 Pi 4pi 8pi 16pi

Mathematics
2 answers:
Elena-2011 [213]2 years ago
8 0

Answer:

The area of semicircle is <u>8π cm</u><u>²</u>.

Step-by-step explanation:

\large{\tt{\underline{\underline{\red{SOLUTION}}}}}

<u>Given</u> :

Here we have given that the diameter of a semicircle is 8 cm. So, the radius will be 8/2 = 4 cm.

<u>Calculating</u> :

Now, finding the area of semicircle by substituting the values in the formula :

{\longrightarrow{\pmb{\sf{Area_{(Semicircle)} =  \dfrac{1}{2}( \pi {r}^{2})}}}}

{\longrightarrow{\sf{Area_{(Semicircle)} =  \dfrac{1}{2}\Big( \pi {(4)}^{2}\Big)}}}

{\longrightarrow{\sf{Area_{(Semicircle)} =  \dfrac{1}{2}\Big( \pi {(4 \times 4)}\Big)}}}

{\longrightarrow{\sf{Area_{(Semicircle)} =  \dfrac{1}{2}\Big( \pi {(16)}\Big)}}}

{\longrightarrow{\sf{Area_{(Semicircle)} =  \dfrac{1}{2}\Big( \pi \times 16\Big)}}}

{\longrightarrow{\sf{Area_{(Semicircle)} =  \dfrac{1}{2}\big( 16\pi \big)}}}

{\longrightarrow{\sf{Area_{(Semicircle)} =  \dfrac{1}{2} \times 16\pi}}}

{\longrightarrow{\sf{Area_{(Semicircle)} =  \dfrac{1}{\cancel{2}} \times  \cancel{16}\pi}}}

{\longrightarrow{\sf{Area_{(Semicircle)} = 1 \times 8\pi}}}

{\longrightarrow{\sf{Area_{(Semicircle)} = 8\pi}}}

\star{\underline{\boxed{\sf{ \purple{Area_{(Semicircle)} = 8\pi \: cm^2}}}}}

Hence, the area of semicircle is 8π cm².

\rule{300}{2.5}

Reika [66]2 years ago
7 0

Answer:

A = 8π cm²

Step-by-step explanation:

The area (A) of a circle is calculated as

A = πr² ( r is the radius )

Here diameter = 8 , then r = 8 ÷ 2 = 4

The area of half a circle is then

A = \frac{1}{2} π × 4² = \frac{1}{2} × π × 16 = 8π cm²

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the numbers of girls in the choir is 4 times the number of boys in the choir .the total number of students is 60..how many girls
Inessa05 [86]
First, make up some variables to represent the number of Girls and Boys in the choir.  

B = number of boys
G = number of girls

You know that there are 4 times as many girls in the choir as boys.  Therefore, the equation you can write is:
\frac{B}{G} =  \frac{1}{4}

If you cross-multiply, then you get the simplified equation:
G = 4B

Intuitively this makes sense since if you multiplied the number of boys in the class by 4, that would be equal to the number of girls you have.

Now, we know that the total class size is 60. So girls plus boys equals 60:
G+B = 60

To solve the equation, replace the G in this equation with the replacement you found before, 4B.
G + B = 60 -->
4B + B = 60 -->
5B = 60 -->
B = 12

However, you are trying to find the number of girls, so plug the answer back into your equation.
G + B = 60 -->
G + 12 = 60 -->
G + 12 -12 = 60 - 12 -->
G = 48

The number of girls you have is 48.

6 0
3 years ago
I dont understand this question. Also if anyone is on geometry byu part two let me know and we can work together !
damaskus [11]

Answer:

Area of circle R = 75π un² or ≈235.5 un²

Step-by-step explanation:

The problem says that m∠TRS = 120º. The total number of degrees in a circle is 360º. 120º is a third of 360º. Therefore, we can prove that the shaded sector is a third of the circle.

The problem then says that the area of the shaded sector is 25π and we have to calculate the area of the entire circle. Since we already know that the shaded sector is a third of the circle, we can simply multiply 25π by 3 in order to calculate the area of t he entire circle.

25π × 3 = 75π.

Area of circle R = 75π un² or ≈235.5 un²

4 0
3 years ago
the ratio of boys to girls at the beach clean up was 7:8 if there are 42 boys how many girls are there
Len [333]
48 girls are there. Given that there is a ratio of boys to girls of 7:8. Then divide 42 boys by 7 boys which equals 6. After, multiply 6 by 8 girls equals 48 girls.

4 0
3 years ago
Can anyone help me on this one?
sertanlavr [38]

Answer:

6

Step-by-step explanation:

a=1/2 b*h

a=1/2 3*4

a=1/2 12

a=6

:)

7 0
3 years ago
Read 2 more answers
If x^2-x-6 and x^2+3x-18 hacpve a common factor (x-a) then find the value of a.​
DedPeter [7]

Answer:

a = 3

Step-by-step explanation:

Factor both expressions

x² - x - 6

Consider the factors of the constant term (- 6) which sum to give the coefficient of the x- term (- 1)

The factors are - 3 and + 2 , since

- 3 × 2 = - 6 and - 3 + 2 = - 1 , thus

x² - x - 6 = (x - 3)(x + 2)

-----------------------------------

x² + 3x - 18

consider factors of constant term (- 18) which sum to give the coefficient of the x- term (+ 3)

The factors are + 6 and - 3 , since

6 × - 3 = - 18 and 6 - 3 = + 3 , thus

x² + 3x - 18 = (x + 6)(x - 3)

Both expressions have a common factor of (x - 3)

Compare with (x - a ), then a = 3

3 0
2 years ago
Read 2 more answers
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