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ladessa [460]
3 years ago
7

HELP PLEASE THIS IS DUE TODAY

Mathematics
1 answer:
nikklg [1K]3 years ago
3 0

Answer:

112 approximately

Step-by-step explanation:

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When 2(3/5 x + 2/3 y - 1/4 x -1 1/2 y + 3 )is simplified, what is the resulting expression?
vovangra [49]

Answer:

Simplifying  the expression: 2(\frac{3}{5}x+\frac{2}{3}y-\frac{1}{4}x-1\frac{1}{2}y +3) we get \mathbf{42x-100y-360}

Step-by-step explanation:

We need to simplify the expression: 2(\frac{3}{5}x+\frac{2}{3}y-\frac{1}{4}x-1\frac{1}{2}y +3)

First we will solve terms inside the bracket

2(\frac{3}{5}x+\frac{2}{3}y-\frac{1}{4}x-1\frac{1}{2}y +3)

Converting mixed fraction 1\frac{1}{2} y into improper fraction, we get: \frac{3}{2}y

Replacing the term:

2(\frac{3}{5}x+\frac{2}{3}y-\frac{1}{4}x-\frac{3}{2}y +3)

Now, taking LCM of: 5,3,4,2 we get 60

Now multiply 60 with each term inside the bracket

2(\frac{3}{5}x\times60+\frac{2}{3}y\times60-\frac{1}{4}x\times60-\frac{3}{2}y\times60 +3\times60)\\2(3x\times12+2y\times20-1x\times15-3x\times30-3\times60)\\2(36x+40y-15x-90y-180)

Now, combine like terms

2(36x-15x-90y+40y-180)\\2(21x-50y-180)

Now, multiply all terms with 2

42x-100y-360

So, Simplifying  the expression: 2(\frac{3}{5}x+\frac{2}{3}y-\frac{1}{4}x-1\frac{1}{2}y +3) we get \mathbf{42x-100y-360}

3 0
3 years ago
certain computer virus can damage any file with probability 35%, independently of other files. Suppose this virus enters a folde
Ksivusya [100]

Answer:

0.623 is the probability that between 800 and 850 files get damaged.

Step-by-step explanation:

We are given the following information:

We treat virus can damage computer as a success.

P( virus can damage computer) = 35% = 0.35

The conditions for normal distribution are satisfied.

By normal approximation:

\mu = np = 2400(0.35) = 840\\\sigma = \sqrt{np(1-p)} = \sqrt{2400(0.35)(1-0.35)} = $$23.36

We have to evaluate probability that between 800 and 850 files get damaged.

P(800 \leq x \leq 850) = P(\displaystyle\frac{800 - 840}{23.36} \leq z \leq \displaystyle\frac{850-840}{23.36}) = P(-1.712 \leq z \leq 0)\\\\= P(z \leq 0.428) - P(z < -1.712)\\= 0.666 - 0.043 = 0.623 = 62.3\%

P(800 \leq x \leq 850) = 62.3\%

0.623 is the probability that between 800 and 850 files get damaged.

8 0
3 years ago
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