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2 years ago

Y = sin (x + 60°), What transformation does + 60° cause to the sine graph?

Mathematics

1 answer:

Goshia [24]2 years ago

5 0

Answer:

3. There is a phase shift (Horizontal shift).

Step-by-step explanation:

Use desmos to help you

Graph

y=sin(x+60)

y=sin(x)

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2 years ago

Bus stop Restaurant sell 3/4 as many cheeseburgers as they do with hamburgers on any given day. If there are a total of 42 burge

schepotkina [342]

Answer:

24cb 18 hb

Step-by-step explanation:

Let's call C the number of cheese burger sold and H the number of hamburgers.

As the cheeseburger sold are 3/4 of hamburgers, we can represent with the following equation:

C= (3/4)H (equation 1)

The total of burgers sold are the total of cheeseburger plus the total of hamburgers, and the sum 42. The equation representing it is:

C + H = 42

Replacing C by its value of eq. 1:

(3/4)H + H = 42

(3/4)H + (4/4)H = 42

(7/4) H = 42

Dividing both sides by (7/4)

H = 42/(7/4)

H= 42*(4/7)

H= (42/7)*4

H= 6*4

H=24

Then, C is:

C=(3/4)H

C=(3/4)*24

C= 3*24/4

C=72/4

C=18

We can verify it summing C+H

C+H=24+18=42 verified!

6 0

3 years ago

Which expression represents the number 2i4−5i3+3i2+−81‾‾‾‾√ rewritten in a+bi form?

vichka [17]

Answer:

The expression $-1+14i$ represents the number $2i^4-5i^3+3i^2+\sqrt{-81}$ rewritten in a+bi form.

Step-by-step explanation:

The value of $i$ is $i=\sqrt{-1}[tex] or [tex]i^{2}=-1[\tex].Now [tex]i^{4}$ in term of $i^{2}[\tex] can be written as, [tex]i^{4}=i^{2}\times i^{2}$

Substituting the value,

$i^{4}=\left(-1\right)\times \left(-1\right)$

Product of two negative numbers is always positive.

$\therefore i^{4}=1$

Now $i^{3}$ in term of $i^{2}[\tex] can be written as, [tex]i^{3}=i^{2}\times i$

Substituting the value,

$i^{3}=\left(-1\right)\times i$

Product of one negative and one positive numbers is always negative.

$\therefore i^{3}=-i$

Now $\sqrt{-81}$ can be written as follows,

$\sqrt{-81}=\sqrt{\left(81\right)\times\left(-1\right)}$

Applying radical multiplication rule,

$\sqrt{ab}={\sqrt{a}}\sqrt{b}$

$\sqrt{\left(81\right)\times\left(-1\right)}={\sqrt{81}}\sqrt{-1}$

Now, $\sqrt{\left(81\right)=9$ and $\sqrt{-1}}=i$

$\therefore \sqrt{\left(81\right)\times\left(-1\right)}=9i$

Now substituting the above values in given expression,

$2i^4-5i^3+3i^2+\sqrt{-81}=2\left(1\right)-5\left(-i\right)+3\left(-1\right)+9i$

Simplifying,

$2+5i-3+9i$

Collecting similar terms,

$2-3+5i+9i$

Combining similar terms,

$-1+14i$

The above expression is in the form of a+bi which is the required expression.

Hence, option number 4 is correct.

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3 years ago