$\text{Given that AB bisects the line segment CD at the point M,}\\
\text{And CD bisects the line segment AB at the point M. so M is the }\\
\text{midpoint of both the line segements AB and CD.}\\
\\
\text{also we have given a relation that, }AB=4\times CM\\
\text{and we need to find a relation between AM and CD.}\\
\\
\text{observe that since M is the midpoint of CD, so we have }CD=2\times CM\\
\\
\Rightarrow CM=\frac{CD}{2}$

$\text{and M is midpoint of AB, so }AB=2\times AM\\
\\
\text{so with these substitutions, the given realtion gives}\\
\\
AB=4\times CM\\
\\
\Rightarrow 2\times AM=4\times \frac{CD}{2}\\
\\
\Rightarrow 2\times AM=2\times CD\\
\\
\Rightarrow AM=CD$

Hence the relationship between AM and CD is : AM=CD

4 0

3 years ago

A chess club with 25 members is electing a new president. Abdul received 23 votes. What percentage of the club members voted for

cluponka [151]

Answer

92%

Explanation

23 out of 25 people voted Abdul.

So that means $\frac{23}{25}$ people voted Abdul.

When you divide 23 by 25 you get 0.92 which is 92% (multiply by 100).

You divide because a fraction means the numerator divided by the denominator.

8 0

3 years ago