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kotykmax [81]
2 years ago
11

2.

Mathematics
1 answer:
dimaraw [331]2 years ago
3 0

Answer:

-7 < -4 < 0 < 7

Step-by-step explanation:

Given

Change: -4, 7, -7 and 0

Required

Compare them

From the list of given options, we can observe that the inequality < is used in all options.

This implies that we arrange from least to highest

The least is -7

Then, -4

Then 0

And lastly, 7

So, we have:

-7 < -4 < 0 < 7

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Simplified (4x3 - 5x2 + 3x) + (-2x3 - x2 + 6x)
bogdanovich [222]

Answer:

<em>Answer is</em><em> </em><em>imaginary</em><em> </em><em>root</em><em>s</em>

Step-by-step explanation:

({4x}^{3}  -  {5x}^{2}  + 3x) + ( -  {2x}^{3}  -  {x}^{2}  + 6x) \\ 2 {x}^{3}  - 6 {x}^{2}  + 9x = 0 \\ dividing \: by \: x \\ 2  {x}^{2}  - 6x + 9 = 0 \\ dividin g\: by \: 2 \\  {x}^{2}  - 3x +  \frac{9}{2}  = 0 \\ shifting \: the \: constant \: term \: on \: right \: side \\  {x}^{2}  - 3x =  -  \frac{9}{2}  \\ adding \:  \frac{1}{2}  \times (coefficient \: of \: x) \: whole \: square \\

On solving the above mentioned equation we get some imaginary values.

<em> </em><em> </em><em> </em><em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

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3 years ago
How do you find an area of a triangle when you just have two sides and an angle?
Olenka [21]
You have to use sin, cos, tan and find the length of the last side and other angles. Then you have to put an imaginary line down the middle and use the sin, cos, tan to find the height and then do 1/2 base times height.
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