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3 years ago

Help !!! ..............

Mathematics

1 answer:

arlik [135]3 years ago

7 0

The second one is the answer, apply distance formula you get the distance between (-2,0) and (1,sqrt(7)) is 4, means the point lies on the circle

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A train goes at a constant speed. If it covers 150 miles in 2 1 2 hours, What distance would it cover in 3 hours?

Rus_ich [418]

The answer is 4.24 I just multiplied

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4 years ago

Let g(x)x and h(x)<br> . Evaluate .

Maurinko [17]

9514 1404 393

Answer:

h(g(x)) = (1/5)x² +4/5

Step-by-step explanation:

$(h\circ g)(x)=h(g(x))=h(x^2+2) = \dfrac{(x^2+2)+2}{5}=\dfrac{x^2+4}{5}\\\\\boxed{(h\circ g)(x)=\dfrac{1}{5}x^2+\dfrac{4}{5}}$

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3 years ago

B is opposite __________.

sukhopar [10]

Answer: OPTION D.

Step-by-step explanation:

By definition, the opposite side of a triangle is that side that is on the opposite direction of an angle.

As you can see, the triangle ABC shown in the figure attached in the problem has the angles: ∠A, ∠B and ∠C.

Then, the angle ∠A is opposite to BC, the angle ∠B is opposite to AC and the angle ∠C is opposite to AB.

Therefore, you can conclude that the answer is the option D, which is: AC.

3 0

3 years ago

Which of the following definite integrals could be used to calculate the total area bounded by the graph of y = x^3 – 3x^2 + 2x

castortr0y [4]

Answer: The correct option is second, i.e. ,"2 times the integral from 0 to 1 of the quantity x cubed minus 3 times x squared plus 2 times x, dx".

Explanation:

The given equation is,

$y=x^3-3x^2+2x$

It can be written as,

$f(x)=x^3-3x^2+2x$

Find the zeros of the equation. Equation the function equal to 0.

$0=x^3-3x^2+2x$

$x(x^2-3x+2)=0$

$x(x^2-2x-x+2)=0$

$x(x-2)(x-1)=0$

So, the three zeros are 0, 1 and 2.

The graph of the equation is shown below.

From the given graph it is noticed that the enclosed by the curve and x- axis is lies between 0 to 2, but the area from 0 to 1 lies above the x-axis and area from 1 to 2 lies below the x-axis. So the function will be negative from 1 to 2.

The area enclosed by curve and x-axis is,

$A=\int_{0}^{1}f(x)dx+\int_{1}^{2}[-f(x)]dx$

$A=\int_{0}^{1}f(x)dx-\int_{1}^{2}f(x)dx$

From the graph it is noticed that the area from 0 to 1 is symmetric or same as area from 1 to 2. So the total area is the twice of area from 0 to 1.

$A=2\int_{0}^{1}f(x)dx$

$A=2\int_{0}^{1}[x^3-3x^2+2x]dx$

Therefore, The correct option is "2 times the integral from 0 to 1 of the quantity x cubed minus 3 times x squared plus 2 times x, dx".

3 0

3 years ago

Where does the graph of y=-3x-18 intersect the x-axis

brilliants [131]

<span>a line crosses the x axis when y = 0
0 = -3x - 18

Add 3x to both sides
3x = -18

Divide both sides by 3
x = -6

Graph intersects x axis at point
(-6, 0)
</span>

6 0

3 years ago

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