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Darina [25.2K]
3 years ago
14

Which shape has at least one one pair of perpendicular sides?

Mathematics
1 answer:
Nookie1986 [14]3 years ago
5 0

Answer:

the square

Step-by-step explanation:

perpendicular = 90 degrees

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What is the value of xin the diagram?<br><br> A. 9<br> B. 8<br> C. 7<br> D. 6
RoseWind [281]

Answer:

7

Step-by-step explanation:

The ratio of the similar triangles is

14       49

---- = ------

2          x

Using cross products

14x = 2*49

14x = 98

Divide by 14

14x/14 = 98/7

x =7

7 0
3 years ago
X+ B = c<br> Over 4<br><br> Solve for X
expeople1 [14]

Answer:

x = c^{4} - b

-Amaya

5 0
3 years ago
Help me solve this algebra 2 question.​
Ivenika [448]

Answer:

A

Step-by-step explanation:

Alright, this may come out weird on computer, but here we go.

First, you want to change this into a multiplication problem, with Keep change flip. So now it's (c^2-c-20/c^2-6c+5) * (3c-3/c^2-16). You then want to simplify some number down.

You can simplify the first part using the X game (not sure if you know this), but you put the c value at the top, and the B value at the bottom, and the two sides blank. These two values must add to equal the C value, but multiply to equal the B value, so you get -5 and 4 for the numerator of the top. Following this formula, and using difference of perfect squares, you'll end up with the following.

(c-5)(c+4)/(c-5)(c-1) * 3(c-1)/(c+4)(c-4)

You then need to cancel out your different groups, so you'll cancel out (c-5), (c+4), (c-1).

After all that, you'll end up with 3/c-4, so the answer is A.

8 0
3 years ago
2y/5y cube + 4y square + 6y
timama [110]

Answer:

here down is the answer

(2y/5y)^3+4y^2+6y

8y^3/125y^3 +16y^2+6y

8/125+16y^2+6y

8/125+16y^2+6y=0

16y^2+6y+8/125=0

it is in the form of quadratic equation

formula :

x=(-b+-square root of b^2-4ac) /2a

here a=16,b=6&c=8/125

x=(-b+-square root of b^2-4ac)/2a

x=(-6+-square root of 36-4.09)/2a here 4.09 came by calculation

x=(-6+-31.91)/2

so

x=(-6+31.91)/2 first (+);

x=25.91/2

x=12.955;

x=(-6-31.91)/2 then(-);

x=-37.91/2

x=-18.955 ;

ans is = 12.955&-18.955;

6 0
3 years ago
Inequalities
charle [14.2K]

for all of these, you just have to divide by -1 to make the variable positive however you have flip the inequality sign when you divide by a negative number.

c > 1

-2 > v

y > 1

z > 6

1 > w

4 0
4 years ago
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