Pls help me with this! Thank u !!

Ms. Jan brought in cookies of her class. She gave out half of them in the morning. At lunch, she gave out 12 more. She then had

Svetach [21]

Answer:

Jan brought 44 cookies

Step-by-step explanation:

To solve this problem, we need to work backwards. First, we have 10 cookies left at the end of the day. At lunch, she gave away 12 cookies. This means that Ms. Jan had 22 cookies at lunch since

10 + 12 = 22

In the morning, Ms. Jan gave out half of her cookies. This means that she started with twice as many cookies as she had at the beginning of lunch.

22 x 2 = 44

Ms. Jan brought 44 cookies.

7 0

3 years ago

Simplify (5^1/3)^3.

pentagon [3]

Answer:

The correct option is C. 5

Therefore,

$(5^{\frac{1}{3})^{3}\ =\ \d5$

Step-by-step explanation:

Simplify

$(5^{\dfrac{1}{3})^{3}=?$

Solution:

Using Identity

$(x^{a})^{b}=x^{(a\times b)}$

So in the given expression

$x = 5\\a=\dfrac{1}{3}\\\\b=3$

Therefore,

$(5^{\frac{1}{3})^{3}\ =\ \d5^{(\dfrac{1}{3}\times 3)}=\d5^{1}=\d5$

Therefore,

$(5^{\frac{1}{3})^{3}\ =\ \d5$

6 0

3 years ago

I need help with these

tia_tia [17]

Answer:

Step-by-step explanation:

5) -7 (-15w + 21) + 3(18 - 27w)

Step 2: 105w - 81w - 147 + 54

6)

step 3: 24w - 93

7 0

2 years ago

A scientist measures a substance to be 0.8 grams. Calculate the percent of error in the measurement. Show all work for full cred

Volgvan

You'll need to give a bit more information for the question to be answered. You can only calculate the percentage of error if you know what the mass of the substance *should be* and what you've *measured* it to be.

In other words, if a substance has a mass of 0.55 grams and you measure it to be 0.80 grams, then the percent of error would be:

percent of error = { | measured value - actual value | / actual value } x 100%

So, in this case:

percent of error = { | 0.80 - 0.55 | / 0.55 } x 100%
percent of error = { | 0.25 | / 0.55 } x 100%
percent of error = 0.4545 x 100%
percent of error = 45.45%

So, in order to calculate the percent of error, you'll need to know what these two measurements are. Once you know these, plug them into the formula above and you should be all set!

6 0

3 years ago

5. If position of object x = 3 sinΘ – 7 cosΘ then motion of object is bounded between position.

lesya692 [45]

9514 1404 393

Answer:

±√58 ≈ ±7.616

Step-by-step explanation:

The linear combination of sine and cosine functions will have an amplitude that is the root of the sum of the squares of the individual amplitudes.

|x| = √(3² +7²) = √58

The motion is bounded between positions ±√58.

_____

Here's a way to get to the relation used above.

The sine of the sum of angles is given by ...

sin(θ+c) = sin(θ)cos(c) +cos(θ)sin(c)

If this is multiplied by some amplitude A, then we have ...

A·sin(θ+c) = A·sin(θ)cos(c) +A·cos(θ)sin(c)

Comparing this to the given expression, we find ...

A·cos(c) = 3 and A·sin(c) = -7

We know that sin²+cos² = 1, so the sum of the squares of these values is ...

(A·cos(c))² +(A·sin(c))² = A²(cos(c)² +sin(c)²) = A²(1) = A²

That is, A² = (3)² +(-7)² = 9+49 = 58. This tells us the position function can be written as ...

x = A·sin(θ +c) . . . . for some angle c

x = (√58)sin(θ +c)

This has the bounds ±√58.

3 0

3 years ago