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valkas [14]
2 years ago
9

Please help me! With 3 and 7! I’ll mark brainliest

Mathematics
1 answer:
Katena32 [7]2 years ago
4 0

Answer:

Multiply

Step-by-step explanation:

and add the last but one answer

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Simplify the following;<br><br> 8v + w + 7 - 8v + 2w<br> 4c² + 6c - 3c² - 2c - 3<br><br> Thanks!
Dominik [7]

Answer:

3w+7

c^2 + 4c - 3

Step-by-step explanation:

8v+w+7-8v+2w

8v-8v +w+2w +7

0+3w+7

3w+7

4c^2+6c-3c^2-2c-3

4c^2-3c^2 + 6c-2c -3

c^2+4c-3

3 0
3 years ago
What is equivalent to 24b-34ab
jarptica [38.1K]
This is what I got as the answer, 2b x (12-17a)
6 0
2 years ago
Ayden had a goal of finishing painting at least 80%, percent of the 500square meters of a house's walls by today. He actually fi
choli [55]

Answer:

yes Ayden Painted 415 square meters more than his goal

7 0
3 years ago
a person invest in 9000 in a bank. the bank pays 5% interest compounded semi annually. to the nearest tenth of a year, how long
QveST [7]

Answer:

10.1 years.

Step-by-step explanation:

It is given that,

Principal = 9000

Rate of interest = 5%

No. of times interest compounded = 2 times in an year

Amount after certain time = 14800

The formula for amount:

A=P(1+\frac{r}{n})^{nt}

where, P is principal, r is rate of interest, n is no. of times interest compounded in an year and t is time in years.

Substitute the given values in the above formula.

14800=9000(1+\frac{0.05}{2})^{2t}

\frac{14800}{9000}=(1+0.025)^{2t}

1.644=(1.025)^{2t}

Taking log both sides.

\log(1.644)=\log(1.025)^{2t}

\log(1.644)=2t\log(1.025)    [\because \log a^b=b\log a]

\frac{\log(1.644)}{2\log(1.025)}=t

t=10.066

t=10.1

Therefore, the required time is 10.1 years.

3 0
3 years ago
I need help ASAP!!! Please explain how to solve the answer.
Pani-rosa [81]

Answer:

Does the answer help you?

Please choose my answer as a brainliest answer and please rate.

It take a few minutes to solve your question.

8 0
2 years ago
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