This is my answer.I hope this is useful.
1 answer:
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Answer:
For this case we can use the theorem of Existence and uniqueness that says:
Let p(t) , q(t) and g(t) be continuous on [a,b] then the differential equation given by:
has unique solution defined for all t in [a,b]
If we apply this to our equation we have that p(t) =0 and and
We see that is not defined at t =0, so the largest interval containing 1 on which p,q and g are defined and continuous is given by
And by the theorem explained before we ensure the existence and uniqueness on this interval of a solution (unique) who satisfy the conditions required.
Step-by-step explanation:
For this case we have the following differential equation given:
With the conditions y(1)= 1 and y'(1) = 7
The frist step on this case is divide both sides of the differential equation by t and we got:
For this case we can use the theorem of Existence and uniqueness that says:
Let p(t) , q(t) and g(t) be continuous on [a,b] then the differential equation given by:
has unique solution defined for all t in [a,b]
If we apply this to our equation we have that p(t) =0 and and
We see that is not defined at t =0, so the largest interval containing 1 on which p,q and g are defined and continuous is given by
And by the theorem explained before we ensure the existence and uniqueness on this interval of a solution (unique) who satisfy the conditions required.
Answer:
262 in
Step-by-step explanation:
the equation for volume of a sphere is : r
so replacing the number of the radius into the equation, it would look like:
r
which gives you 523.59878 in
but since it's a hemisphere, you'd divide it in half, which gives you 261.79939.
since you're rounding off to the nearest whole number, you're answer is 262 in