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3 years ago

What is the inverse of function f?

Mathematics

1 answer:

Arte-miy333 [17]3 years ago

4 0

9514 1404 393

Answer:

C. f^-1(x) = (∛(x+1))/4

Step-by-step explanation:

The inverse function can be found by solving x = f(y) for y.

$f(y)=x\\\\64y^3-1=x\\\\64y^3=x+1 \qquad\text{add1}\\\\4y=\sqrt[3]{x+1} \qquad\text{cube root}\\\\y=\dfrac{\sqrt[3]{x+1}}{4} \qquad\text{divide by 4}\\\\\boxed{f^{-1}(x)=\dfrac{\sqrt[3]{x+1}}{4}}$

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What are the roots of the equation 2x^2 + 9x divided by 6=0?

tensa zangetsu [6.8K]

2x^2 + 9x =6×0 so 2x^2 + 9x = 0 so we factorise x and we get x×(2x+9)=0 so x=0 divided by 2x+9 so it is 0 one root, 2x+9=0 divided by x so we get 2x+9=0 and 2x=-9 and x=-9÷2 and the second root is -4.5. I hope it is helpful. Please give me brainliest

3 0

4 years ago

Pls helpppppp this stuff makes no sense

yulyashka [42]

Answer:

x = 5

Step-by-step explanation:

a || b and a line intersecting them is their transversal.

$\therefore m\angle 1=m\angle 5\\(corresponding \:\angle 's) \\\\\therefore 60 - 2x = 70 - 4x\\\\\therefore 4x - 2x = 70 - 60\\\\\therefore 2x = 10\\\\\therefore x =\frac{10}{2} \\\\\huge \orange {\boxed {\therefore x = 5}}$

4 0

3 years ago

A rectangle has width that is 6 meters less than the length. The area of the rectangle is 280 square meters. Find the dimensions

salantis [7]

Dimensions are length 20 meter and width 14 meter

Solution:

Let "a" be the length of rectangle

Let "b" be the width of rectangle

Given that,

A rectangle has width that is 6 meters less than the length

Width = length - 6

b = a - 6

The area of the rectangle is 280 square meters

The area of the rectangle is given by formula:

$Area = length \times width$

Substituting the values we get,

$Area = a \times (a-6)\\\\280 = a^2-6a\\\\a^2-6a -280=0$

Solve the above equation by quadratic formula

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\\quad x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=1,\:b=-6,\:c=-280:\quad a_{1,\:2}=\frac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:1\left(-280\right)}}{2\cdot \:1}$

$a =\frac{6 \pm \sqrt{36+1120}}{2}\\\\a = \frac{6 \pm \sqrt{1156}}{2}\\\\a = \frac{6 \pm 34}{2}\\\\Thus\ we\ have\ two\ solutions\\\\a = \frac{6+34}{2} \text{ or } a = \frac{6-34}{2}\\\\a = 20 \text{ or } a = -14$

Since, length cannot be negative, ignore a = -14

Thus solution of length is a = 20

Therefore,

width = length - 6

width = 20 - 6 = 14

Thus dimensions are length 20 meter and width 14 meter

6 0

4 years ago

Evaluate f(x) when x= 9

noname [10]

Answer:

The value of f(9) is equal to 498.

Step-by-step explanation:

Given that,

f(x) = 6x²+12

We need to find the value of x(9).

Put x = 9 in the given function.

f(9) = 6(9)²+12

f(9) = 498

So, the value of f(9) is equal to 498.

7 0

3 years ago

Help ...........................................................................

Lynna [10]

Answer: D

Step-by-step explanation: $\frac{2}{6} =\frac{1}{3} = 0,(3)$

7 0

4 years ago