To factor this fraction, you have be be aware of two special factoring formula:
a^3<span> + </span>b^3<span> = (</span>a<span> + </span>b)(a^2<span> – </span>ab<span> + </span>b^2<span>)
</span><span>(a+b)³ = a³ + 3a²b + 3ab² + b³
You can see the top part in this case is (x+y)^3, and the bottom (denominator) can be factor into (x+y)(x^2-xy+y^2)
we can cancel (x+y), so what we have left is (x+y)^2/(x^2-xy+y^2)
or (x^2+2xy+y^2)/(x^2-xy+y^2)
</span>
Given that X <span>be the number of subjects who test positive for the disease out of the 30 healthy subjects used for the test.
The probability of success, i.e. the probability that a healthy subject tests positive is given as 2% = 0.02
Part A:
</span><span>The probability that all 30 subjects will appropriately test as not being infected, that is the probability that none of the healthy subjects will test positive is given by:
</span>

<span>
Part B:
The mean of a binomial distribution is given by
</span>

<span>
The standard deviation is given by:
</span>

<span>
Part C:
This test will not be a trusted test in the field of medicine as it has a standard deviation higher than the mean. The testing method will not be consistent in determining the infection of hepatitis.</span>
Answer:
Option E - sigma greater than or equal to $327
Step-by-step explanation:
In this question, we are testing whether the standard deviation of the base price of a certain type of all-terrain vehicle is at least $327.
Now, standard deviation is denoted by the symbol sigma(σ). Since the test is saying it should be at least $327, it means it should either be equal to $327 or greater than $327.
Thus, we would use the symbol ≥ which means "greater than or equal to".
Thus, the claim as a mathematical statement would be;
sigma greater than or equal to $327
Answer:
a) 30 kangaroos in 2030
b) decreasing 8% per year
c) large t results in fractional kangaroos: P(100) ≈ 1/55 kangaroo
Step-by-step explanation:
We assume your equation is supposed to be ...
P(t) = 76(0.92^t)
__
a) P(10) = 76(0.92^10) = 76(0.4344) = 30.01 ≈ 30
In the year 2030, the population of kangaroos in the province is modeled to be 30.
__
b) The population is decreasing. The base 0.92 of the exponent t is the cause. The population is changing by 0.92 -1 = -0.08 = -8% each year.
The population is decreasing by 8% each year.
__
c) The model loses its value once the population drops below 1/2 kangaroo. For large values of t, it predicts only fractional kangaroos, hence is not realistic.
P(100) = 75(0.92^100) = 76(0.0002392)
P(100) ≈ 0.0182, about 1/55th of a kangaroo
Answer:
x = 11/3 = 3 2/3
y = 13/3 = 4 1/3
Step-by-step explanation:
Here, we want to solve the system of equations simultaneously
x + y = 8
2x -3 = y
From the second equation, we have an equation for y
we can simply proceed to substitute this into the first equation
x + 2x - 3 = 8
3x - 3 = 8
3x = 8 + 3
3x = 11
x = 11/3
Recall;
y = 2x - 3
y = 2(11/3) - 3
y = 22/3 - 3
y = (22-3(3))/3
y = (22-9)/3 = 13/3