Answer:
cos34°
sin56°
Step-by-step explanation:
Sin(2x+42)= sin90-(3x+13)
Sin(2x+42) = sin(90-13-3x)
Sin(2x+42) = sin(77-3x)
2x + 42 = 77-3x
5x. = 35
X = 7
If x = 7
cos(3x+13) = cos((3*7)+13)
cos(3x+13) = cos(21+13)
cos(3x+13)= cos34
And
sin(2x+42) = sin((2*7)+42)
sin(2x+42)= sin (14+42)
sin(2x+42) = sin56
The answer is 3s squared over r to the 4th
it should look like a fraction with 3s squared as the numerator (on top) && r to the 4th as the denominator (on bottom)
hope this was helpful, math is my strength so post more if you need help!
Answer: 
Step-by-step explanation:
To answer this, we have to use quadratic equations.
We can represent this by using information given to us.
Knowing that a parabola peaks at its vertex, and the flare goes from its launch site (x = 0) and hits the ground 30m from the launch site (x = 30), we know that the flare peaks 15 meters away horizontally from the launch point.
We also know that the y-intercept is 0, because it is fired from the ground.
Knowing that the vertex for the parabola is (15, 200) and the y-intercept is (0, 0), we can model an equation.
Vertex form is:
, where (h, k) is the vertex.

We can plug the y-intercept, (0, 0), into this equation to find a:

1L = 1,000mL
therfore
52L = 52 × 1,000mL = 52,000 mL
52L = 52,000mL !!!!