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krek1111 [17]
3 years ago
10

Amy's car gets 32 miles per gallon. If her car's tank holds 15 gallons of gas, and she wants to keep a minimum of 1 gallon of ga

s in the tank for safety, how far (in miles) can Amy drive after filling up before she needs to fill up again?
Mathematics
1 answer:
velikii [3]3 years ago
4 0

Answer:

448 miles

Step-by-step explanation:

Amy's car can hold 15 gallons of gas. Provided that each gallon can drive her 32 miles. This means that 15 gallons can drive her 480 miles.

15 gallons x 32 miles = 480 miles

However, she needs to keep 1 gallon of gas in the tank for safety reasons. So we have to subtract 1 gallon from 15 gallons.

15 gallons - 1 gallon = 14 gallons

Now, let's compute again.

14 gallons x 32 miles = 448 miles

Amy can drive 448 miles before she needs to fill up the tank again.

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The lengths of pregnancies in a small rural village are normally distributed with a mean of 264.1 days and a standard deviation
KiRa [710]

Answer:

The range of the 95% data (X) =  238.3 days <  X < 289.9 days

Step-by-step explanation:

Given;

mean of the normal distribution, m = 264.1 days

standard deviation, d = 12.9 days

between two standard deviation below and above the mean is 96% of all the data.

two standard deviation below the mean = m - 2d

                                                                   = 264.1 - 2(12.9)

                                                                   = 238.3 days

two standard deviation above the mean = m + 2d

                                                                    = 264.1 + 2(12.9)

                                                                     = 289.9 days

The middle of the 95% of most pregnancies would be found in the following range;

238.3 days <  X < 289.9 days

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