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AnnZ [28]
3 years ago
5

What's 14/63 in simplest form

Mathematics
1 answer:
serious [3.7K]3 years ago
8 0
You would cancel the common factors in the numerator and denominator. 

Exact Form: 
2/9 

Decimal Form: 
0.222222222.....
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Find the period of an electromagnetic wave of wavelength 2.20 × 10–2 m. A. 1.36 × 1010 s c. 7.33 × 10–11 s b. 4.54 × 101 s d. 6.
vovangra [49]

Answer:

7.33 * 10^-11 s

Step-by-step explanation:

Period, T = 1 / f

c = fλ

λ = 2.20 × 10^–2 m

c = speed of light = 3 * 10^8 m

f = c / λ

f = 3 * 10^8 ÷ 2.20 × 10^–2 m

f = (3/2.2) * 10^(8-(-2))

f = 1.364 * 10^10

T = 1/f

T = 1 / 1.364 * 10^10

T = 7.33 * 10^-11 s

4 0
3 years ago
Jackie wants to create a scale drawing of the poster shown below: A rectangle is shown. The length of the rectangle is labeled 4
ValentinkaMS [17]
C. Half of 4 is 2ft and half of 8 is 4ft.
7 0
3 years ago
For example, for a circle of diameter 4 cm, the circumference is approximately<br> cm.
Simora [160]

Answer:

the diameter is 4 cm which means the radius is 2 cm. Diameter divided by two will give you the radius. The formulae for circumference is 2 π⋅r. So the circumference would be 4 π.

Step-by-step explanation:

7 0
2 years ago
. A building in the shape of a rectangular prism needs to be painted. Some facts about the building are shown below. The buildin
Softa [21]

Answer:

(2)(120)(80) + (2)(120)(50) - (4)(60)(5²)

Step-by-step explanation:

The lateral faces of the building are the 4 sides of the building consisting:

2 rectangles of 120 ft by 80 ft

Area of the two rectangular faces = (2)(120)(80)

And

2 rectangles of 120 ft by 50 ft

Area of the two rectangular faces = (2)(120)(50)

✔️Total lateral surface area of the building = (2)(120)(80) + (2)(120)(50)

Note: we are asked to find the expression that represents the total surface area that needs to be painted given that there are 60 windows on each lateral face of the building of the shape of a square with side lengths of 5 ft.

Therefore, the total lateral surface area of the building that will be painted = total lateral surface of the building - total area covered by the 60 windows on each face of the building

Surface area covered by 60 windows in the 4 lateral face of the building = (4)(60)(5²)

✅total lateral surface area of the building that will be painted = (2)(120)(80) + (2)(120)(50) - (4)(60)(5²)

6 0
2 years ago
All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be
Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

A = a + (A \cap B)

In which a is the probability that a student is proficient in reading but not mathematics and A \cap B is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

B = b + (A \cap B)

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

(A \cup B) + C = 1

In which

(A \cup B) = a + b + (A \cap B)

65% were found to be proficient in both reading and mathematics.

This means that A \cap B = 0.65

78% were found to be proficient in mathematics

This means that B = 0.78

B = b + (A \cap B)

0.78 = b + 0.65

b = 0.13

85% of the students were found to be proficient in reading

This means that A = 0.85

A = a + (A \cap B)

0.85 = a + 0.65

a = 0.20

Proficient in at least one:

(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98

What is the probability that the student is proficient in neither reading nor mathematics?

(A \cup B) + C = 1

C = 1 - (A \cup B) = 1 - 0.98 = 0.02

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0
3 years ago
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