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3 years ago

WILL MARK BRAINLIEST!!!!!

Mathematics

1 answer:

xenn [34]3 years ago

5 0

Answer:

An example that may contradict the definition is that if you are trying to find chords, they wont be the same distance as finding the radius. The way that you can change this definition is by saying that "A circle is the set of all points in a plane that are the same distance from a fixed point called the center."

Hope this helps you!

You might be interested in

Find the measure of a central angle of a regular polygon with 10 sides

Paraphin [41]

Answer:

114 degrees

Step-by-step explanation:

The formula to find the measure of all angles in a regular polygon is $(n-2)180$ , where n = total number of sides.

Thus, we substitute n for 10, and you get:

$(10-2)180=1440$

If the shape is a regular polygon and it has ten sides, meaning all sides are equal, then all you do is divide 1440 by 10, to get the final answer of 114.

A central angle in a regular ten-sided polygon would be 144 degrees.

5 0

3 years ago

The Length of a rectangle is 5 centimeters less than twice its width . The perimeter of the rectangle is 80cm. What are the dime

borishaifa [10]

Perimeter is the sum of all a shapes sides.

with that in mind, we know a rectangle has four sides. with 2 pairs being the same.

The length as told is, 5 centimeters less than two times the width. Two times the width would be 2w and five less than that would be minus five. so the length is 2w - 5

now to find the perimeter we do two times the width + two times the length.

2w + 2(2w -5) = 80.
Distribute: 2w + 4w - 10 = 80
Add ten to both sides and combine the 2w & 4w:
6w = 90
Divide both sides by 6: w = 15.

with this we know the width is 15. to find length plug in 15 to the 2w - 5 equation.

2(15) - 5 = 30 - 5 = 25.

Slap on the units and width = 15 cm, length = 25 cm

7 0

3 years ago

Please help me figure out the answers !

OverLord2011 [107]

Answer:

Step-by-step explanation:

44,89,989,54,211,26,2,78,54,51

6 0

3 years ago

Prove 2√(x) + 1/√(x + 1) <= 2√(x+1) for all x in [0,inf)

EleoNora [17]

Start by multiplying each side of the inequality by $\sqrt{x + 1}$ and simplifying:

$2 \sqrt x + \frac{1}{\sqrt{x+1}} \leq 2 \sqrt{x + 1}$
$(2 \sqrt x + \frac{1}{\sqrt{x+1}})(\sqrt{x + 1}) \leq (2 \sqrt{x + 1})(\sqrt{x + 1})$
$2 \sqrt{x(x + 1)} + 1 \leq 2(x + 1)$
$2 \sqrt{x^2 + x} + 1 \leq 2x + 2$
$2 \sqrt{x^2 + x} \leq 2x + 1$
$\sqrt{x^2 + x} \leq x + \frac{1}{2}$

From here, we can square both sides to get

$x^2 + x \leq (x + \frac{1}{2})^2$
$x^2 + x \leq x^2 + x + \frac{1}{4}$
$0 \leq \frac{1}{4}$ , which is always true.

3 0

3 years ago

Factor.

tekilochka [14]

Answer:

Answer is C

Step-by-step explanation:

(x + 6)(x + 2)

5 0

3 years ago