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frez [133]
3 years ago
7

Sec0 = -

ign="absmiddle" class="latex-formula"> and cot0 < 0, find exact values of tan0 and sin0.
Mathematics
2 answers:
enot [183]3 years ago
8 0

Answer:

Solution given;

Sec θ=-\frac{13}{12}

cotθ< 0,

It lies in second quadrant.

where sin and cosec is positive.

Now

\frac{1}{cosθ}=-\frac{13}{12}

cosθ=\frac{12}{13}

\frac{b}{h}=\frac{12}{13}

b=12

h=13

By using Pythagoras law

p=\sqrt{13²-12²}=5

Now

exact values of tan θ=\frac{p}{b}=\frac{5}{12}

since it lies in II quadrant

<u>tan θ</u><u>=</u><u>-</u>\frac{5}{12}

and

sinθ=\frac{p}{h}=\frac{5}{13}

since it lies in II quadrant

<u>sin</u><u> </u><u>θ</u><u>=</u>\frac{5}{13}

ziro4ka [17]3 years ago
3 0

Answer:

tan 0 = -2.4

sin 0 = 0.3846

Step-by-step explanation:

sec 0 = -13/12, and cot 0 < 0

the angle 0 is in quadrant II

sec 0 = -13/12 = cos 0 = -12/13 = x/r

=> y = √13²-12²=√169-144=√25=5

so,

tan 0 = y/x = -12/5 = -2.4

sin 0 = y/r = 5/13 = 0.3846

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\qquad\qquad\huge\underline{{\sf Answer}}

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