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3 years ago

A building is 75 feet tall. On a scale model , 5cm will represent 3 feet How many cm tall will the model be

Mathematics

2 answers:

Alex787 [66]3 years ago

8 0

Just do 75 divided by 3 and that gives you 25 do 25x5 and that gives you 125 the answer is 125.

Answer 125cm

zysi [14]3 years ago

7 0

125 cm idk if this is right

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Find the slope and y-intercept. 6y = 5(x - 6) The slope is The y-intercept is

lbvjy [14]

Answer: The slope-intercept form is y = m x + b y = m x + b, where m m is the slope and b b is the y-intercept. y = m x + b y = m x + B. Simplify 5 6 ⋅ ( x − 6) 5 6 ⋅ ( x - 6). Tap for more steps... Apply the distributive property. y − 6 = 5 6 x + 5 6 ⋅ − 6 y - 6 = 5 6 x + 5 6 ⋅ - 6. Combine 5 6 5 6 and x x.

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3 years ago

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Kent invested $5000 in a retirement plan. He allocated x dollars of the money to a bond account that earns 4% interest per year

eduard

Answer: The answers are given below.

Step-by-step explanation: Given in the question that Kent invested $5000 in a retirement plan. He allocated x dollars of the money to a bond account that earns 4% interest per year and the rest to a traditional account that earns 5% interest per year.

(A) Let, '$y' be the amount of money Kent invested in the traditional account, then we have

$y=5000-x.$

This is the required expression.

(B) After 1 year, total money in the bond account will be

$M_b=x+\dfrac{1\times 4\times x}{100}=x+\dfrac{x}{25}=\dfrac{26}{25}x,$

and amount of money in the traditional account will be

$M_t=(5000-x)+\dfrac{1\times 5\times (5000-x)}{1000}=(5000-x)+\dfrac{5000-x}{200}\\\\\\\Rightarrow M_t=\dfrac{201(5000-x)}{200}.$

Therefore, total amount invested after 1 year will be

$M=M_b+M_t=\dfrac{26}{25}x+\dfrac{201(5000-x)}{200}=\dfrac{208x+1005000-201x}{200}\\\\\\\Rightarrow M=\dfrac{7x+1005000}{200}.$

(C) If x = $500, then we have

$M=\dfrac{7\times 500+1005000}{200}=\dfrac{1008500}{200}=\dfrac{10085}{2}=5042.5.$

Thus, Kent will have $5042.5 in his retirement plan after 1 year.

4 0

3 years ago

Consider f(x)=2|x|

shusha [124]

Answer:

Please check the explanation.

Step-by-step explanation:

As we know that the average rate of change of f(x) in the closed

interval [a, b] is

$\frac{f\left(b\right)-f\left(a\right)}{b-a}$

Given the interval [a, b] = [0, 4]

$f(x)=2|x|$

$f(b)=f(2)=2\cdot \:4$ ∵ $\mathrm{Apply\:absolute\:rule}:\quad \left|a\right|=a,\:a\ge 0$

$= 8$

$f(x)=2|x|$

$f(a)=f(0)=2\cdot \:0$ ∵ $\mathrm{Apply\:absolute\:rule}:\quad \left|a\right|=a,\:a\ge 0$

$= 0$

so the average rate of change :

$\frac{f\left(b\right)-f\left(a\right)}{b-a}=\frac{8-0}{4-0}$

$=\frac{8}{4}$

$= 2$

We know that a rate of change basically indicates how an output quantity changes relative to the change in the input quantity. Here, it is clear the value of y increase with the increase of input.

6 0

3 years ago

A rectangle has an area of 347.13cm^2 if the length is 20.3cm what is the width of the rectangle

vivado [14]

347.13^2 = 120499.237

120499.237 / 20.3

= 5935.923

4 0

3 years ago

Read 2 more answers

In a survey of consumers aged 12 and older, respondents were asked how many cell phones were in use by the household. (No two

bogdanovich [222]

Answer:

The probability that his/her household has four or more cell phones in use is 0.122 or 12.2%.

Step-by-step explanation:

The complete question is: In a survey of consumers aged 12 and older, respondents were asked how many cell phones were in use by the household. (No two respondents were from the same household.) Among the respondents, 215 answered "none", 280 said "one", 362 said "two", 149 said "three," and 140 responded with four or more. A survey respondent is selected at random. Find the probability that his/her household has four or more cell phones in use. Is it unlikely for a household to have four or more cell phones in use? Consider an event to be unlikely if its probability is less than or equal to 0.05.

We are given that among the respondents, 215 answered "none", 280 said "one", 362 said "two", 149 said "three," and 140 responded with four or more.

A survey respondent is selected at random.

As we know that the probability of any event is calculated as;

Probability = $\frac{\text{Favorable number of outcomes}}{\text{Total number of outcomes}}$

Here, we have to find the probability that his/her household has four or more cell phones in use;

Number of respondent having four or more cell phones in use = 140

Total number of respondents asked = 215 + 280 + 362 + 149 + 140 = 1146

So, the required probability = $\frac{140}{1146}$

= 0.122 or 12.2%

No, it is not unlikely for a household to have four or more cell phones in use because the probability is not less than or equal to 0.05 but in actual it is greater than 0.05.

6 0

3 years ago