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Mazyrski [523]
3 years ago
6

An amusement park thrill ride swings its riders back and forth on a pendulum that spins. Suppose the swing arm of the ride is 62

feet in length, and the axis from which the arm swings is about 64 feet above the ground. What is the height of the riders above the ground at the peak of the arc? Round to the nearest foot if necessar
PLEASE HELP ​

Mathematics
1 answer:
babunello [35]3 years ago
7 0

Answer:

118ft

Step-by-step explanation:

dont ask how i got it i just got the answer from my teacher but they didnt show me the work. ur welcome

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HELP ME PLEASEEEEEEEEEEEEEEEEEEE
Debora [2.8K]

Answer:

heyy matee...

see

Vertices (V) = 8

Faces (F) = 6

Edges (E) => F + V - E = 2 (EULER'S FORMULA)

so 6 + 8 - 2 = E => E = 12

now just look at options

and however its a common thing that if Vertices are 8 and Faces are 6 and Edges are 12 then it is cube or cuboid

and another name of cuboid is rectangular prism ;)

hence answer is option c - rectangular prism

brainliest possible ?

3 0
2 years ago
What can you press to move around the calculator when making lists?
erastova [34]

Answer:

The arrow buttons on the calculator

Step-by-step explanation:

It mostly matters on what kind of calculator have but most calculators are like that.

5 0
3 years ago
$15,074 is invested, part at 14% and the rest at 5%. If the interest earned from the amount invested at 14% exceeds the interest
Flauer [41]

The rate at 14% and 5% are $12, 883 and $2191 respectively.

<h3>How to determine the rate</h3>

Given that;

Invested amount = $ 15, 074 at 14% and 5%

Let rate at 14% = x

rate at 5% = y

We have rate at 9% exceeds that of 5% by $1694. 07

Hence,

0. 14x = 0. 05y + $1694. 07 ⇒ equation 1

x + y = $15, 074 ⇒ equation 2

Make 'x' the subject

x = 15, 074 - y

Substitute in equation 2

0. 14(15, 074 - y) = 0. 05y + $1694. 07

Expand the expression

2, 110. 36 - 0. 14y = 0.05y + 1694. 07

Collect like terms

416. 29 = 0. 19y

Make 'y' the subject

y = \frac{416. 29}{0. 19}

y = $2, 191

Substitute the value in equation 2

x + y = $15, 074

x = $15, 074 - y

x = $15, 074 - 2191

x = $12, 883

Therefore , the rate at 14% and 5% are $12, 883 and $2191 respectively.

Learn more about simultaneous equations here:

brainly.com/question/16863577

#SPJ1

4 0
1 year ago
What is 100,000 to the 10th power.
oee [108]

Answer:

100,000^10 = 10^50 = 100,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000

Step-by-step explanation:

100,000^10 = (10^5)^10 = 10^(5 * 10) = 10^50

The answer is a very large number number which is 1 followed by 50 zeros.

100,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000

6 0
3 years ago
1
pantera1 [17]

Answer:

The probability of winning directly is, as you calculated, 8/36, and the probability of losing directly is (1+2+1)/36=4/36.

For the remaining cases, you need to sum over all remaining rolls. Let p be the probability of rolling your initial roll, and q=6/36=1/6 the probability of rolling a 7. Then the probability of rolling your initial roll before rolling a 7 is p/(p+q), and the probability of rolling a 7 before rolling your initial roll is q/(p+q). Thus, taking into account the probability of initially rolling that roll, each roll that doesn't win or lose directly yields a contribution p2/(p+q) to your winning probability.

For p=5/36, that's

(536)25+636=2511⋅36,

and likewise 16/(10⋅36) and 9/(9⋅36) for p=4/36 and p=3/36, respectively. Each of those cases occurs twice (once above 7 and once below), so your overall winning probability is

836+236(2511+1610+99)=244495=12−7990≈12−0.007.

Step-by-step explanation:

Suppose you throw a 4 and let p(4) your winning probability. At your next roll you have a probability 3/36 of winning (you throw a 4), a probability 6/36 of losing (you throw a 7) and a probability 27/36 of repeating the whole process anew (you throw any other number). Then:

p(4)=336+2736p(4),so thatp(4)=13.

Repeat this reasoning for the other outcomes and then compute the total probability of winning as:

ptot=836+336p(4)+436p(5)+…

7 0
2 years ago
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