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Doss [256]
3 years ago
9

I need some help with 6 and 7 thank you for helping

Mathematics
2 answers:
Alik [6]3 years ago
8 0
#6 . 6 cups #7 2 pairs (1,4) (2,8)
DedPeter [7]3 years ago
3 0
The answer is 13. Is that what you needed.
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Somebody help me with this please .
erastova [34]

Step-by-step explanation:

12. Cos 60° = 8/c

0,5 = 8/c

0,5 c = 8

c = 16

D² = V16²-8²

= V256-64

=V192 = V16×12 = 4V12

= 4V4×3 = 8V3

13. Cos 30° = 6/b

V3/2 = 6/b

V3 b = 12

b = 12/V3

b/Sin B = a /sin A

b/Sin90° = 6/ sin 60°

<u>b</u> = <u> </u><u> </u><u> </u><u>6</u><u> </u><u> </u><u> </u>

1 V3/2

b× <u>V3</u> = 6

2

b = 6× 2/V3

= 12/V3

8 0
3 years ago
I need to find the greatest common factor of <img src="https://tex.z-dn.net/?f=40s%5E3t%5E5" id="TexFormula1" title="40s^3t^5" a
solong [7]

Answer:

\large\boxed{GCF(40s^3t^5,\ 2s^4t^4,\ 14s^6t^6)=2s^3t^4}

Step-by-step explanation:

40s^3t^5=\boxed2\cdot2\cdot2\cdot5\cdot \boxed{s\cdot s\cdot s}\cdot \boxed{t\cdot t\cdot t\cdot t}\cdot t\\\\2s^4t^4=\boxed2\cdot  \boxed{s\cdot s\cdot s}\cdot s\cdot \boxed{t\cdot t\cdot t\cdot t}\\\\14s^6t^6=\boxed2\cdot7\cdot  \boxed{s\cdot s\cdot s}\cdot s\cdot s\cdot s\cdot \boxed{t\cdot t\cdot t\cdot t}\cdot t\cdot t\\\\GCF(40s^3t^5,\ 2s^4t^4,\ 14s^6t^6)=\boxed2\cdot  \boxed{s\cdot s\cdot s}\cdot\boxed{t\cdot t\cdot t\cdot t}=2s^3t^4

7 0
3 years ago
1/10 of 400,000 is 10 times as much as?
mote1985 [20]
40,000 is the answer
5 0
3 years ago
Angela weighs 15% less than she did one year ago. Which of the statements below is true?
Elden [556K]

The current weight W_c is 15% less than the weight Angela had 1 year ago (W). Or we can write,

W_c=(1-\frac{15}{100}) W\\ W_c=\frac{85}{100}W\\.

Thus Angela,s current weight is 85% of her weight one year ago.


8 0
3 years ago
Read 2 more answers
There are eight pencils in a package. How many packages will be needed for 28 children if each children gets pencils
Ahat [919]
4 packages
8 × 4 = 32
6 0
3 years ago
Read 2 more answers
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