The cosine function with the given characteristics is:
f(x) = 3*cos(x/2 - pi).
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How to get the cosine function?</h3>
The general cosine function is:
f(x) = A*cos(kx + p)
Where A is the amplitude and p is the phase, then we know that:
A = 3
p = -pi
Then we have:
f(x) = 3*cos(kx - pi)
And the period is equal to 4pi, then we must have that:
k*(x + 4pi) - pi = k*x - pi + 2pi
k = 1/2
Then the function is:
f(x) = 3*cos(x/2 - pi).
If you want to learn more about cosine functions:
brainly.com/question/4372174
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Okay so this is a wild guess but I would say 12. The whole angle is 90, but only 1/3 of that is in the smaller portion of the triangle. So, I assumed that 1/3 of the length of the whole triangle. Three times 6 is 18 and minus AD is 12. So BD=12? This is my best guess hope it helps
This is a geometric sequence which represent exponential decay. For any sequence, if r^2, the common ratio squared, is less than one, it is exponential decay, or:
f=ir^t
If r^2<1, it is exponential decay. In this case r=2/3, so it is exponential decay.
This is a kind of oddly written question, but since it is absolute value, your answer is correct.
Hope this Helps!