Answer:
this is my alt, btw. I'm taking these points back from myself before they get stolen
Answer:
0.2514 = 25.14% probability that the diameter of a selected bearing is greater than 85 millimeters.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

Find the probability that the diameter of a selected bearing is greater than 85 millimeters.
This is 1 subtracted by the pvalue of Z when X = 85. Then



has a pvalue of 0.7486.
1 - 0.7486 = 0.2514
0.2514 = 25.14% probability that the diameter of a selected bearing is greater than 85 millimeters.
I would say 18 because 790-610= 180 and 180÷10= 18
Answer:
(y^3+2)/y^2
Step-by-step explanation:
9x² - 12x + 4
write the equation with two middle terms that multiply to give 36
9x² - 6x - 6x + 4
by factorisation
3x(3x - 2) - 2(3x - 2)
(3x - 2)²
Thus OPTION A