Answer:
The first car is traveling at a speed of
s1=62 mi/hr.
The second car is traveling at a speed of s2=67 mi/hr.
Step-by-step explanation:
Let t be the amount of time the cars are traveling
s1=248/t and s2=268/t
We are told:
s1=s2-5
That is
248/t=268/t-5
⇒248=268- 5t
⇒5t=20
⇒t=4
s1=248/4=62
s2=268/4=67
Answer:
x = 17
Step-by-step explanation:
3(x-12)=15
->
x-12+12=5+12
