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3 years ago

Find the slope and Y-intercept for each table, and then write an equation.

Mathematics

1 answer:

Leni [432]3 years ago

8 0

Answer:

a. Slope = 2; y-intercept = 2

b. Slope = 2; y-intercept = 3

c. Slope = 2; y-intercept = -1

d. Slope = -2; y-intercept = 5

e. Slope = -3; y-intercept = -5

d. Slope = -2; y-intercept = 1

Step-by-step explanation:

I Hope That This Helps! :)

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What are the x-intercepts of x^2– 3x = 4?

Sindrei [870]

Answer:

x^2-3x=4

x^2-3x-4=0

x^2-4x+x-4=0

x(x-4)+1(x-4)=0

(x+1)(x-4)=0

x=-1,4

x- intercepts in the point (-1,0) and (4,0)

Step-by-step explanation:

3 0

3 years ago

Rewrite each problem so that x appears on only one side

Vlad1618 [11]

Answer:

x = -5/21

Step-by-step explanation:

Step 1: Write equation

2(12x - 1) = (21x - 49)/7

Step 2: Solve for x

Multiply both sides by 7: 14(12x - 1) = 21x - 49
Distribute 14: 168x - 14 = 21x - 49
Subtract 21x on both sides: 147x - 14 = -49
Add 14 to both sides: 147x = -35
Divide both sides by 147: x = -5/21

5 0

3 years ago

Triangle PQR has two known interior angles of 24°, and 100°.

Tamiku [17]

180-24=5
180-56=34
Both are equal
D

3 0

3 years ago

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Jessica buys a computer that originally cost $1,015 using a 20% off coupon. Sales tax in her city is 5%. How much will she pay f

Sedaia [141]

Answer:

852.6

Step-by-step explanation:

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3 years ago

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How are exponents and radicals used to present roots of real numbers

MissTica

Answer:

$\sqrt[n]{a} =a^{\frac{1}{n}}$

Explanation:

Roots of real numbers can be represented by radicals or by exponents.

First, I present some examples to show how exponents and radicals are related, and then generalize.

$\sqrt{4}=4^{(\frac{1}{2})}=(2^2)^\frac{1}{2}=(2)^{\frac{2}{2}}=2^1=2\\\\\\\sqrt{25}=(25)^{\frac{1}{2}}=(5^2)^{\frac{1}{2}}=(5)^{\frac{2}{2}}=5^1=5$

$\sqrt[3]{8}=(8)^{\frac{1}{3}}=(2^3)^{\frac{1}{3}}=(2)^{\frac{3}{3}}=2^1=2$

When you write 5² = 25, then 5 is the square root of 25.

And in general, if n is a positive integer and $a^n=x$ , then $a$ is the nth root of x.

Also, if n even (and positive) and $a$ is positive, then $a^{\frac{1}{n}}$ is the positive nth root of $a$

Thus,

$\sqrt[n]{a} =a^{\frac{1}{n}}$

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3 years ago