A pharmacist has 40% and 80% of iodine solutions on hand. How many liters of each iodine solution will be required to produce 4 liters of a 50% iodine mixture?
.
Let x = liters of 40% iodine
then
4-x = liters of 80% iodine
Using algebra:
.40x + .80(4-x) = .50(4)
.40x + 3.20-.80x = 2
3.20-.40x = 2
x = 4 liters (40% iodine)
80% iodine:
4-x = 4-4 = 0 liters needed (80% iodine)
Answer:
15 chocolate chip
Step-by-step explanation:
1/4 of 20 is 5
this means there are 5 peanut butter cookies.
so 20-5= 15
this means there are 15 chocolate chip cookies
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-3(x+(3))^2-4 is the answer
M-(M x 0.16) and M-(.84) because the first one you need to multiply to find what 16% of m is then subtract that by m for the second one you subtract.
Answer:
13.2''
Step-by-step explanation:
lets ? be x
x² + 15² = 20²
x² = 20² - 15²
x = √175
x = 13.2''
so missing length = 13.2''
