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AnnyKZ [126]
3 years ago
12

Help on 3&4 I don't get what in the Mumbo jumbo their talking about

Mathematics
2 answers:
ehidna [41]3 years ago
7 0
Number 3 is c. and 4 is b 
erica [24]3 years ago
3 0
3) It's basically asking how many 7 ounce servings can be made out of a 64 ounce container. Divide 64 by 7 and you will get a decimal but their asking for full servings so round down to the closest whole number 
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Will give brainliest if correct.
Nataly [62]

Answer:

The answer would be, 81cm.

Step-by-step explanation:

36÷4=9

9×9=81

8 0
3 years ago
Read 2 more answers
Sandy bought 3/4 yard of ribbonand 2/3 yard of white ribbon how much ribbon did she but altogether
Neko [114]
To answer this you need to find the LCD (least common denominator) 2/3times4=8/12 and 3/4times3=9/12 and 9+8=17 then 17-12=5 so she bought 1 5/12 yards of ribbon
7 0
3 years ago
Find the indefinite integral. (Use C for the constant of integration.)
mart [117]

Answer:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \frac{1}{8} (x^3-x^2+x)^8+C

tep-by-step explanation:

In order to find the integral:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx

we can do the following substitution:

Let's call

u=(x^3-x^2+x)

Then

du = (3x^2-2x+1) dx

which allows us to do convert the original integral into a much simpler one of easy solution:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx  = \int\ {u^7 \, du = \frac{1}{8} \,u^8 +C

Therefore, our integral written in terms of "x" would be:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \frac{1}{8} (x^3-x^2+x)^8+C

7 0
3 years ago
Subtract 0.58 - 0.21. What is the place value of the 7 in the difference? ones tens tenths hundredths
hoa [83]

Answer:

hundredths place



8 0
3 years ago
Read 2 more answers
When a certain drug is taken orally, the concentration of the drug in the patient's bloodstream after t minutes is given by
sineoko [7]
The time when the maximum serum concentration is reached is obtained by equating the derivative of C(t) to 0.
i.e. dC(t)/dt = 0.06 - 2(0.0002t) = 0.06 - 0.0004t = 0
0.0004t = 0.06
t = 0.06/0.0004 = 150
Therefore, the maximum serum concentration is reached at t = 150 mins

The maximum concentration = 0.06(150) - 0.0002(150)^2 = 9 - 0.0002(22,500) = 9 - 4.5 = 4.5
Therefore, the maximum concentration is 4.5mg/L
7 0
3 years ago
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