Answer:
I think it would be 15
Step-by-step explanation:
Answer:
option C. 
Step-by-step explanation:
we have that
The point (-5,-12) belong to the III quadrant
so
The value of the cosine is negative
Applying the Pythagoras Theorem
Find the value of the hypotenuse

The value of cosine of angle θ is the ratio between the side adjacent to angle θ and the hypotenuse

Answer:
When x = 3, the solutions to the expressions are–20 and –20
Step-by-step explanation:
–4(3) – 8 Multiply
-12 - 8 Subtract
-20
-2(3 + 1) - 2(3 + 3) Simplify in the parentheses
-2(4) - 2(6) Multiply
-8 - 12 Subtract
-20
Answer: 80 miles for the first ship, and 150 miles for the other.
Explanation:
First thing we should do is correspond each number with a letter:
Let x be the distance travel by ship heading east
Let y be the distance travel by ship heading south
y = x + 70 -- (1)
sqrt(x^2 + y^2) = 170 -- (2)
Subtract (1) into (2):
sqrt(x^2 + (x + 70)^2) = 170
x^2 + x^2 + 140x + 4900 = 28900
2x^2 + 140x - 24000 = 0
x ^2 + 70x - 12000 = 0
(x - 80)(x + 150) = 0
x = 80 or -150
Since the distance for the first ship can’t be negative, therefore, x = 80 -- (3)
Subtract (3) into (1), therefore, y = 150
Hope this helps! :)
Answer:
3:40 p.m.
Step-by-step explanation:
Add 74 minutes to 1:25 p.m.; the improperly formed result witll be 1:99 p.m.; to express this properly, add 1 hour to this time and subtract 60 minutes from it:
2:39 p.m. (time at which Avery gets off the bus)
If Avery walked 61 minutes to get home and we want to know what time she arrived, we add 61 minutes to 2:39 p.m., obtaining 2:100 p.m., which must in turn be re-written as 3:40 p.m.
Avery arrived home at 3:40 p.m.
Note: another way in which to do this problem is to add 74 minutes and 61 minutes, obtaining 135 minutes, and then adding 135 minutes to 1:25 p.m. and making the necessary adjustments to the result:
1:25 p.m. + 135 minutes = 1:160 p.m., or (recognizing that 120 min = 2 hours)
3:40 p.m.