The correct answer would be D, the median 86.5.
In this set of data most of the values are in the 80's or 90's. There is only 1 number that is outside of this range, that is the value 0. It is an outlier.
When we have an outlier, the median generally gives us the better measure of central tendency.
Answer:
c = -4
Step-by-step explanation:
If f(x) = 2x^3 - x + c and f(2) = 10, plug in 2 for the x values in the function and make the function output 10.
10 = 2(2^3) - 2 + c Now, we only have to deal with one variable, that is c.
10 = 2(8) - 2 + c
10 = 16 - 2 + c
10 = 14 + c
-4 = c After simplifying, we get that c is -4.
To check this, plug in 2 for x, and -4 for c in the function. If the function produces 10 as the result, the halleluja!
f(2) = 2(2^3) - 2 - 4
f(2) = 2(8) - 2 - 4
f(2) = 16 - 2 - 4
f(2) = 10
I think you have to email them or something lol
