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Natali [406]
3 years ago
13

Simplify 4 to the 11th power over 4 to the -8th power

Mathematics
1 answer:
madam [21]3 years ago
3 0

Answer:

274878070200

Step-by-step explanation:

4 to the power 11 = 4194304

4 to the power -8 = 0.00001525878

4194304/0.00001525878 = 274878070200

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Which equation has the components of 0 = x2 – 9x – 20 inserted into the quadratic formula correctly? x = StartFraction negative
AnnZ [28]

Answer:

x=\frac{9+/-\sqrt{(-9)^2-4\,(1)\,(-20)} }{2\,(1)}

Step-by-step explanation:

Recall that the quadratic formula gives you the pattern to follow in order to find the solutions to a quadratic equation of the form: ax^2+bx+c=0

It tells us that we need to use the parameters a,\, b, and c in the following formula in order to get the answers for the x-values that solve it:

x=\frac{-b+/-\sqrt{b^2-4\,a\,c} }{2\,a}

so, in our case, a=1, b=-9, and c=-20

then, replacing these values in the formula, we obtain:

x=\frac{-b+/-\sqrt{b^2-4\,a\,c} }{2\,a}\\x=\frac{-(-9)+/-\sqrt{(-9)^2-4\,(1)\,(-20)} }{2\,(1)}\\x=\frac{9+/-\sqrt{(-9)^2-4\,(1)\,(-20)} }{2\,(1)}

Which looks like the third expression you are listing (although it is a little hard to read)

7 0
3 years ago
Read 2 more answers
Heinz has a list of possible functions. Pick one of the g(x) functions below, show how to find the zeros, and then describe to H
MrRissso [65]

<span>g(x) = x3 – x2 – 4x + 4 </span>

<span>You can find the zeroes by factoring the equation. x<span>2  </span>(x - 1) - 4(x - 1) = 0 </span>

<span>(x2 - 4) (x - 1) = 0 </span>

(x + 2) (x - 2) (x - 1) = 0

x = 2, -2, and 1

The following are the key features of g(x):

g'(x) yields the slope

g''(x) yields the concavity

g'(x) = 0 provides the critical points

<span>g''(x) = 0 provides the point of inflection</span>
8 0
3 years ago
Need help on questions 1, and 2 please
finlep [7]
1. See the attached graph.

2. All translations are considered rigid motion. The locations of points on the figure do not change relative to one another.

7 0
3 years ago
The roots of the equation 3x²-2x-4=0 are J and K. Evaluate J² + K².
melamori03 [73]

Answer:

28/9

Step-by-step explanation:

If the roots are J and K, then:

3 (x − J) (x − K) = 0

3 (x² − (J+K)x + JK) = 0

So if we factor out the leading coefficient:

3x² − 2x − 4 = 0

3(x² − 2/3x − 4/3) = 0

The coefficient of the second term is the sum of the roots:

J + K = 2/3

And the constant is the product of the roots:

JK = -4/3

If we take the sum of the roots and square it:

(J + K)² = (2/3)²

J² + 2JK + K² = 4/9

And subtract twice the product:

J² + K² = 4/9 − 2JK

J² + K² = 4/9 − 2(-4/3)

J² + K² = 4/9 + 8/3

J² + k² = 28/9

6 0
3 years ago
Your business partner describes this as a high positive correlation. Is your partner correct? Why or why not? (2 points)
zaharov [31]

Answer:

if the points are in a straight line going upward then they are corect

but if the points are scattered they are wrong its hard to answer this question he graph to look at

4 0
3 years ago
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