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3 years ago

Surface Area is [sa1] of the figure.

Mathematics

2 answers:

DochEvi [55]3 years ago

7 0

Zbkxnskz4567(234)321

kobusy [5.1K]3 years ago

5 0

What is the question to answer ?

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How many solutions does the system have?

marishachu [46]

Answer:

{x,y} = {-2,2}

Step-by-step explanation:

Solve equation [2] for the variable y

7y = 7x + 28

y = x + 4

Plug this in for variable y in equation [1]

-8x + 4•(x +4) = 24

-4x = 8

Solve equation [1] for the variable x

4x = - 8

x = - 2

By now we know this much :

x = -2

y = x+4

Use the x value to solve for y

y = (-2)+4 = 2

Solution :

{x,y} = {-2,2}

and this intersects at only one point so your answer is A

3 0

3 years ago

In the following data set, what is the range? 3, 7, 8, 4, 4, 5, 9, 10, 6, 2

OleMash [197]

To find range tou must order the numbers so they are least to greatest. Then you subtract the smallest value from the greatest value.

2,3,4,4,5,6,7,8,9,10

10-2=8

Range=8

8 0

3 years ago

M = - 3 <br> M = -1 <br> M = 1 <br> M = 3 <br> I’m giving out brainlest to whoever helps me

ASHA 777 [7]

Answer:

I would say 3.

Step-by-step explanation:

I would say 3 because if you look at the graph, it goes: 0, 1, 2, 4, 5. Your missing 3. So, I would say 3.

4 0

3 years ago

Find an equation for the nth term of a geometric sequence where the second and fifth terms are -21 and 567, respectively

oksano4ka [1.4K]

Answer:

$x_n=7(-3)^{n-1}$

Step-by-step explanation:

First, write some equations so we can figure out the common ratio and the initial term. The standard explicit formula for a geometric sequence is:

$x_n=ar^{n-1}$

Where xₙ is the nth term, a is the initial value, and r is the common ratio.

We know that the second and fifth terms are -21 and 567, respectively. Thus:

$a_2=-21\\a_5=567$

Substitute them into the equations:

$x_2=ar^{(2)-1}\\-21=ar$

And:

$a^5=ar^{(5)-1}\\567=ar^4$

To find a and r, divide both sides by a in the first equation:

$r=-\frac{21}{a}$

And substitute this into the second equation:

$567=a(\frac{-21}{a} )^4$

Simplify:

$567=a(\frac{(-21)^4}{a^4})$

The as cancel out. (-21)^4 is 194481:

$\frac{567}{1}=\frac{194481}{a^3}$

Cross multiply:

$194481=567a^3\\a^3=194481/567=343$

Take the cube root of both sides:

$a=\sqrt[3]{343} =7$

Therefore, the initial value is 7.

And the common ratio is (going back to the equation previously):

$r=-21/a\\r=-21/(7)\\r=-3$

Thus, the common ratio is -3.

Therefore, the equation is:

$x_n=7(-3)^{n-1}$

5 0

3 years ago

a climber starts descending from 533 feet above sea level and keeps going until she reaches 10 feet below sea level how many fee

otez555 [7]

Answer:

Distance from 533 to -10 is: 533 - (-10) = 533 + 10 = 543

Step-by-step explanation:

Divide the descent into two parts. 1st part: From 533 feet to sea level. 2nd part from sea level to 10 feet below sea level. Add the distance for each of the two parts. Hint: How many feet above or below sea level is sea level?

5 0

3 years ago