Given:
Temperature in the morning = 6°F.
By the late afternoon, the temperature had dropped 9°F.
To find:
The temperature by the late afternoon.
Solution:
Temperature by the late afternoon = Morning temperature - Dropped temperature
Using the given values and the above formula, we get
Temperature by the late afternoon = 6°F - 9°F
Temperature by the late afternoon = -3°F
Therefore, the temperature by the late afternoon is -3°F.
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corresponds to TR. correct option b.
<u>Step-by-step explanation:</u>
In the given parallelogram or rectangle , we have a diagonal RT . We need to find which side is in correspondence with side/Diagonal RT of parallelogram URST .
<u>Side TU:</u>
In triangle UTR , we see that TR is hypotenuse and is the longest side among UR & TU . So , TR can never be equal in length to UR & TU . So there's no correspondence of Side TU with RT.
<u>Side TR:</u>
Since, direction of sides are not mentioned here , we can say that TR & RT is parallel & equal to each other . So , TR is in correspondence with side/Diagonal RT of parallelogram URST .
<u>Side UR:</u>
In triangle UTR , we see that TR is hypotenuse and is the longest side among UR & TU . So , TR can never be equal in length to UR & TU . So there's no correspondence of Side UR with RT.
Hakkakwksoosjanakskwkwkwkmskskwkw
Let us start subtracting 3 cos theta both sides so that we may get all theta terms on left side only
It is now : 4 cos theta - 3 cos theta = - (sqrt3)/ 2
1 cos theta = -( sqrt 3 ) /2
we know cos (pi-x)= - cos x And cos (pi+ x)= - cos (x)
********* let us first use :
- Cos ( pi - theta) = - ( sqrt 3 )/2
this implies cos (pi- theta )= (sqrt 3) /2
cos ( pi - theta )= cos (pi /6)
pi- theta = pi/6
pi- pi/6 = theta
5 pi/6 = theta
one of teh answer is 5 pi/6 . another value of theta would be :
(2pi - 5pi/6)= 7pi/6
Answer: 5 pi/6 and 7 pi/6
Answer:
7 4/5
Step-by-step explanation:
2 2/5 = 12/5
3 1/4 = 13/4
12/5 x 13/4 = 156/20 = 7 16/20
7 16/20 / 4 = 7 4/5
