The perimeter of the polygon is 53.6 units.
Solution:
The reference image to the answer is attached below.
AP = 8, BQ = 7.8 and CR = 11
AP and AR are tangents to a circle from an external point A.
BP and BA are tangents to a circle from an external point B.
CQ and CR are tangents to a circle from an external point C.
<em>Tangents drawn from an external point to a circle are equal in length.</em>
⇒ AP = AR, BP = BQ and CQ = CR
AR = 8
BP = BQ
⇒ BP = 7.8
CQ = CR
⇒ CQ = 11
Perimeter of the polygon = AP + BP + BQ + CQ + CR + AR
= 8 + 7.8 + 7.8 + 11 + 11 + 8
= 53.6
The perimeter of the polygon is 53.6 units.
Answer:


Step-by-step explanation:
The given parameters can be represented as:

Solving (a): P(x < 3)
This is calculated as:
----- i.e. all probabilities less than 3
So, we have:


Solving (b): Expected number of events
This is calculated as:

So, we have:



Express as decimal

Approximate to the nearest integer

Use the points (1, 15000) and (8, 1000) for the slope of the trendline
m = (1000 - 15000)/(8 - 1) = (-14000)/7 = -2000
y = -2000x + b
15000 = -2000(1) + b
15000 = -2000 + b
17000 = b
Equation
y = -2000x + 17000