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In-s [12.5K]
2 years ago
14

4/6-3/8 zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz

Mathematics
2 answers:
lesantik [10]2 years ago
5 0

Answer:

0.29166666666

Step-by-step explanation:

Vesnalui [34]2 years ago
4 0

Answer:

The answer is 7/24 ~hope this helps~

btw, sick pic  B-)

Step-by-step explanation:

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Harriet used the work below to determine the percent equivalent to 1/8.
vampirchik [111]

Step 2 shows the error.

8 0
2 years ago
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What is the outlier of the set of data? 33, 46, 41, 41, 30, 9, 14, 33, 15, 26, 12, 46, 28, 36, 95 ____________________
Delvig [45]
The outlier is 95.

All the numbers are from 9 - 46 EXCEPT for 95

Answer = 95

Hope this helped :) 
7 0
3 years ago
Someone help please, dk what to do
Alekssandra [29.7K]

Step-by-step explanation:

equation format: y = mx + b where m is slope and b is the y intercept.

From the points given we find that it is a horizontal line, which means slope or m = 0. So we know so far:

y = 0x + b or y = b

The y-intercept occurs where x = 0. This occurs at y = -7. So the equation for these two points:

EQUATION: y = -7

(Plotted graph attached)

4 0
1 year ago
How do you estimate 32.17÷ 17
Savatey [412]

Answer:

To estimate you round to 1sf -Significant figure- 30÷20=1.5

3 0
3 years ago
Suppose that it rains in Spain an average of once every 10 days, and when it does, hurricanes have a 8% chance of happening in H
Law Incorporation [45]

Answer:

The <em>probability </em>that it rains in Spain when hurricanes happen in Hartford is <em>0.1127</em>

Step-by-step explanation:

This is a question where you use must use Bayes' Theorem.

The easiest way to do Bayes' type questions is to carefully define your terms.

Let R be the event that it is raining in Spain. R' is the event it isn't.

Let H be the event that it is hurricane in Hartford. H' is the event it isn't.

We know

<em>P(R) = 1/10, </em>

<em>P(H | R) = 0.08, </em>

<em>P(H | R') = 0.07</em> and we want <em>P(R | H)</em>.

<em>Bayes Theorem says P(R | H) = [P(H | R)×P(R)] / P(H) </em>

<em> where</em>

<em>P(H) = P(H | R)×P(R) + P(H | R')×P(R') </em>

<em />

Therefore,

<em>P(R | H) = [P(H | R)×P(R)] / [P(H | R)×P(R) + P(H | R')×P(R')]</em>

<em>P(R | H) = [0.08 × 1/10] / [(0.08 × 1/10) + (0.07 × (1 - 1/10)]</em>

<em>P(R | H) = 8 / 71</em>

<em>P(R | H) = 0.1127</em>

<em></em>

Therefore, the <em>probability </em>that it rains in Spain when hurricanes happen in Hartford is <em>0.1127.</em>

7 0
3 years ago
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