All categories

3 years ago

HELP! Domain/Range of f(x)= 2 SQRT X

Mathematics

1 answer:

jeyben [28]3 years ago

8 0

Answer:

Step-by-step explanation:

I’m in middle school

You might be interested in

Kaylee tell Aimee that the shape is a stop sign has a least one right angle. Aimee says that three are no right angles.who is ri

damaskus [11]

Aimee is correct because a stop sign is an octogon. Octogons contain only obtuse angles.

4 0

3 years ago

Please help me with this math question

Neko [114]

Answer:

C .56

Step-by-step explanation:

well thier are 5 days that are less then 3 days and theirs 9 days in total so you would do 5/9 to get the chance of it being less then 3 days.

5/6 = .555556

3 0

3 years ago

Find dy/dx using first principle<br>x+1/x

JulsSmile [24]

Answer:

The derivative of the function is:

$f'(x)=1-\frac{1}{x^{2}}$

Step-by-step explanation:

The first principle is given by:

$f'(x)=\frac{dy}{dx}=lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h}$

The function here is:

$f(x)=x+\frac{1}{x}$

Now, using the first principle we have:

$f'(x)=lim_{h\rightarrow 0}\frac{(x+h)+\frac{1}{(x+h)}-x-\frac{1}{x}}{h}$

$=lim_{h\rightarrow 0}\frac{h+\frac{1}{(x+h)}-\frac{1}{x}}{h}$

$=lim_{h\rightarrow 0}\frac{h-\frac{h}{x(x+h)}}{h}$

$=lim_{h\rightarrow 0}\frac{h(1-\frac{1}{x(x+h)})}{h}$

$=lim_{h\rightarrow 0}1-\frac{1}{x(x+h)}$

$=1-\frac{1}{x^{2}}$

Therefore, the derivative of the function is:

$f'(x)=1-\frac{1}{x^{2}}$

I hope it helps you!

6 0

2 years ago

Solve for x. Rs/x =1/4 A. X=rs/4 B. X=4/rs C. X=1/4rs D. X=4rs

Burka [1]

The answer is b x=4/rs

6 0

3 years ago

Read 2 more answers

A Quadratic polynomial whose zeroes are 5 and -2 is

andrey2020 [161]

Today I am going to share with you my ideas about my favourite time of the day. All time is great. It is God's gift to us to make or mar ourselves. I respect time whether in the morning, afternoon, evening, or night; I just love time.

5 0

3 years ago

Read 2 more answers