It would be false i think
Answer:
The combined average is 94%
Step-by-step explanation:
for first period, number of students =40
average =96%
for second period, no of students =20
average =90%
but
let
=sum of students for the first period
=sum of students for the second period
for first period;
![\frac{S_{1} }{40} =96%](https://tex.z-dn.net/?f=%5Cfrac%7BS_%7B1%7D%20%7D%7B40%7D%20%3D96%25)
![S_{1}= 96*40=3840](https://tex.z-dn.net/?f=S_%7B1%7D%3D%2096%2A40%3D3840)
for second period,
![\frac{S_{2} }{20} =90%](https://tex.z-dn.net/?f=%5Cfrac%7BS_%7B2%7D%20%7D%7B20%7D%20%3D90%25)
![S_{1}= 90*20=1800](https://tex.z-dn.net/?f=S_%7B1%7D%3D%2090%2A20%3D1800)
therefore the combined average = ![\frac{S_1+S_2}{40+20}](https://tex.z-dn.net/?f=%5Cfrac%7BS_1%2BS_2%7D%7B40%2B20%7D)
that is
![= 94%](https://tex.z-dn.net/?f=%3D%2094%25)
so combined average is 94%
Answer:
162, 163, and 164.
Step-by-step explanation:
Here we will use algebra to find three consecutive integers whose sum is 489. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 489. Therefore, you can write the equation as follows:
(X) + (X + 1) + (X + 2) = 489
To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:
X + X + 1 + X + 2 = 489
3X + 3 = 489
3X + 3 - 3 = 489 - 3
3X = 486
3X/3 = 486/3
X = 162
Which means that the first number is 162, the second number is 162 + 1 and the third number is 162 + 2. Therefore, three consecutive integers that add up to 489 are 162, 163, and 164.
162 + 163 + 164 = 489
We know our answer is correct because 162 + 163 + 164 equals 489 as displayed above.
Answer:
64
Step-by-step explanation:
x-13+2x+1=180
3x-13+1=180
3x-12=180
3x=180+12
3x=192
x=192/3
x=64
X-intercept is the point (x,y) when y=0, i.e.
solve 0=(x+2)/(x-3) =>x=-2, and the x-intercept is (-2,0)
y-intercept is the point (x,y) when x=0, i.e.
solve y=(0+2)/(0-3)=-2/3 => y-intercept is (0,-2/3)