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3 years ago

14

What city is this please no links

2 answers:

Artist 52 [7]3 years ago

7 0

Answer:

fantasy if its wrong im sorry

Inessa [10]3 years ago

5 0

Its Istanbul
Goodluck

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What is the greatest common factor of 20x6y+40x4y2−10x5y5 ?

mestny [16]

The greatest common factor: 20x^6y 40x^4y^2 10x^5y^5 is 10x^4y.
20x^6y = 10x^4y*2x^2
40x^4y^2 = 10x^4y*4y
10x^5y^5 = 10x^4y*y^4

8 0

3 years ago

Initially a tank contains 10 liters of pure water. Brine of unknown (but constant) concentration of salt is flowing in at 1 lite

zhenek [66]

Answer:

Therefore the concentration of salt in the incoming brine is 1.73 g/L.

Step-by-step explanation:

Here the amount of incoming and outgoing of water are equal. Then the amount of water in the tank remain same = 10 liters.

Let the concentration of salt be a gram/L

Let the amount salt in the tank at any time t be Q(t).

$\frac{dQ}{dt} =\textrm {incoming rate - outgoing rate}$

Incoming rate = (a g/L)×(1 L/min)

=a g/min

The concentration of salt in the tank at any time t is = $\frac{Q(t)}{10}$ g/L

Outgoing rate = $(\frac{Q(t)}{10} g/L)(1 L/ min)$ $\frac{Q(t)}{10} g/min$

$\frac{dQ}{dt} = a- \frac{Q(t)}{10}$

$\Rightarrow \frac{dQ}{10a-Q(t)} =\frac{1}{10} dt$

Integrating both sides

$\Rightarrow \int \frac{dQ}{10a-Q(t)} =\int\frac{1}{10} dt$

$\Rightarrow -log|10a-Q(t)|=\frac{1}{10} t +c$ [ where c arbitrary constant]

Initial condition when t= 20 , Q(t)= 15 gram

$\Rightarrow -log|10a-15|=\frac{1}{10}\times 20 +c$

$\Rightarrow -log|10a-15|-2=c$

Therefore ,

$-log|10a-Q(t)|=\frac{1}{10} t -log|10a-15|-2$ .......(1)

In the starting time t=0 and Q(t)=0

Putting t=0 and Q(t)=0 in equation (1) we get

$- log|10a|= -log|10a-15| -2$

$\Rightarrow- log|10a|+log|10a-15|= -2$

$\Rightarrow log|\frac{10a-15}{10a}|= -2$

$\Rightarrow |\frac{10a-15}{10a}|=e ^{-2}$

$\Rightarrow 1-\frac{15}{10a} =e^{-2}$

$\Rightarrow \frac{15}{10a} =1-e^{-2}$

$\Rightarrow \frac{3}{2a} =1-e^{-2}$

$\Rightarrow2a= \frac{3}{1-e^{-2}}$

$\Rightarrow a = 1.73$

Therefore the concentration of salt in the incoming brine is 1.73 g/L

8 0

3 years ago

The water level at Lake Penny changed −1 1/10 in. this year. Next year, it is predicted to change another −1 2/5

frutty [35]

- 1 1/10 + (-1 2/5)

- 1 1/10 + (-1 4/5)

-2 5/10

-2 1/2

7 0

3 years ago

Roberto wants to reduce a drawing that is 12 inches long by 9 inches wide. If his new drawing is 8 inches long, how wide will it

Bess [88]

Answer: It would be 6 inches wide.

Step-by-step explanation: Well two thirds of 12 in. is 8in. So two thirds of 9in. would be 6 inches.

6 0

3 years ago

Read 2 more answers

Louisa drew a polygon with six sides of equal length. If the perimeter of Louisa's polygon is 95.4 centimeters, how long is each

Agata [3.3K]

Answer:

15.9 centimeters

Step-by-step explanation:

the information we have is:

Perimeter: $P=95.4cm$

Number of sides of the polygon: $n=6$

since each side has equal length, we can use the following equation to find the measure of one side of the polygon, the equation for perimeter:

$P=nl$

where n is the number of sides and $l$ is the length of each side.

So we clear for $l$ and we get:

$l=\frac{P}{n}$

and subtituting the known values:

$l=\frac{95.4cm}{6}\\ l=15.9cm$

each side is 15.6 centimeters long

3 0

3 years ago