Answer:
B
Step-by-step explanation:
i hope it helps
#CarryOnLearning
So, this is a rate problem, so the forumla we would get is
2.5g=30
(Note this is not one of the choices), so if we look, there is an equivelent equation.
If we divide both sides by g we get
2.5=30/g
B is the correct answer
2 1/2 = 2.5
12 1/2 = 12.5
This means you can calculate how may times it goes in by dividing it and rounding the number down:
12.5 / 2.5 = 5
*5 can not be rounded down so it stays the same
This means that 2 1/2 goes into 12 1/2 5 times. Hope this helps! :)
Answer:
D) (3.67, 4.73)
Step-by-step explanation:
Confidence Interval for the true average number of homes that a person owns in his or her lifetimecan be calculated using M±ME where
- M is the average number of home owned (4.2)
- ME is the margin of error from the mean
And margin of error (ME) can be calculated as
ME=
where
- z is the corresponding statistic in the given confidence level(1.96)
- s is the standard deviation of the sample(2.1)
- N is the sample size (60)
Putting the numbers we get ME=
≈0.53
Then the 95% confidence interval is 4.2±0.53 or (3.67, 4.73)
(a) If
are mutually exclusive, then

so we have

(b) If
are mutually independent, then




so that


