The slope of the line that passes through the following points is undefined
<em><u>Solution:</u></em>
Given that, We have to find the slope of line passing through two points
Given points are (-1, 5) and (-1, 6)
<em><u>The slope of line is given by formula:</u></em>
From given,
<em><u>Substituting the values we get,</u></em>
Thus the slope is undefined
A) about 14 square units
You have 11 fully filled squares 2 that are mostly filled and 2 that are about half filled
So 11+2+2(1/2)= about 14
Answer:
Step-by-step explanation:
Slope of perpendicular lines = -1
y = 5/2x + 3
-1 ÷ 
= 
(-3 , -5)
Equation of the required line: y - y₁ = m(x -x₁)
y - [5] = ![\frac{-2}{5}(x - [-3])\\](https://tex.z-dn.net/?f=%5Cfrac%7B-2%7D%7B5%7D%28x%20-%20%5B-3%5D%29%5C%5C)
9514 1404 393
Answer:
- domain: [-6, -1)
- range: [-5, 4]
Step-by-step explanation:
You have correctly determined the domain to be from x = -6 to x < -1. In interval notation, that would be ...
[-6, -1)
__
The range is the vertical extent of the graph. It extends from a minimum of y = -5 to a maximum of y = +4 at the top of the curve. In interval notation, that would be ...
[-5, 4]
Double of 50 is 100, so 28*100=2800, now half of the answer is 2800/2=1400
